Question ( please help me )

Com: if a protein contains 150 amino acids, there would be how many codons in the specification to construct it?

Marina86 [1]

If a bacterial protein contains 150 amino acids, then there would be 150 codons in the specification to construct the said protein. A codon is definces as a sequence of 3 RNA or DNA nucleotides which would correspond to a specific amino acid such that if you have 150 amino acids then you would also have 50 codons. THe start of a codon is the first codon that can be found in the messenger RNA that is translated by the ribosome.

8 0

3 years ago

1. Take the reaction: NH3 + O2 + NO + H2O. In an experiment, 3.25g of NH3 are allowed

Rudiy27

Answer:

5.74g of NO

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

4NH3 + 5O2 —> 4NO + 6H2O

Step 2:

Determination of the masses of NH3 and O2 that reacted and the mass of NO produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g

Molar Mass of NO = 14 + 16 = 30g/mol

Mass of NO from the balanced equation = 4 x 30 = 120g

From the balanced equation above,

68g of NH3 reacted with 160g of O2 to produce 120g of NO.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting because it will be used to calculate the maximum yield of the reaction. This is illustrated below:

From the balanced equation above,

68g of NH3 reacted with 160g of O2.

Therefore, 3.25g of NH3 will react with = (3.25 x 160)/68 = 7.65g of O2.

From the simple illustration above, we can see that lesser mass of O2 is needed to react with 3.25g of NH3. Therefore, NH3 is the limiting reactant while O2 is the excess reactant.

Step 4:

Determination of the mass of NO produced from the reaction.

In this case the limiting reactant will be used because all of it were used in the reaction.

The limiting reactant is NH3.

From the balanced equation above,

68g of NH3 reacted to produce 120g of NO.

Therefore, 3.25g of NH3 will react to produce = (3.25 x 120)/68 = 5.74g of NO.

From the calculations made above, 5.74g of NO is produced.

4 0

3 years ago

Can someone help me balance this equation please? Br2 + S2O32– + H2O → Br1– + SO42– + H+

tamaranim1 [39]

Explanation:

Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e

7 0

2 years ago

A sample of nitric acid contains both H3O ions and NO3 ions. This sample has a pH

bearhunter [10]

Answer : The name of positive ion present in this sample is, hydronium ion.

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Ion : An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

As per question, hydronium ion or hydrogen ion is having an oxidation state of +1 called as $H_3O^{+}$ or $H^+$ cation and nitrate ion $NO_3^{-}$ is an anion with oxidation state of -1.