Answer:
0.209 mol/L
Explanation:
Given data
- Mass of copper(lI) sulfate (solute): 11.7 g
- Volume of solution: 350 mL = 0.350 L
The molar mass of copper(Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:
11.7 g × (1 mol/159.61 g) = 0.0733 mol
The molarity of copper(Il) sulfate is:
M = moles of solute / liters of solution
M = 0.0733 mol / 0.350 L
M = 0.209 mol/L
<span>The number of electrons in an atom's outermost valence shell governs its bonding behavior.
In N</span>₂, three electrons are being shared by each nitrogen atom, making a total of 6 shared electrons.
In CCl₄, 4 electrons are being shared by each carbon atom and 1 electron is being shared by each chlorine atom
In SiO₂, 4 electrons are being shared by each silicon atom and 2 electrons are being shared by each oxygen atom.
In AlCl₃, 3 electrons are being shared by each aluminum atom and 1 electron is being shared by each Cl atom
In CaCl₂, 2 electrons are lost by the calcium atom and 1 electron is gained by each chlorine atom
In LiBr, 1 electron is lost by the lithium atom and 1 electron is gained by the bromine atom
whatever u r mixing together will indicated what the reaction or the product will be
Answer:
It depends on the objects mass, the gravitational pull when up or down slopes, and the height of the reference point
