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viktelen [127]
2 years ago
13

You are given a bottle of solid X and three aqueous solutions of X—one saturated, one unsaturated, and one supersaturated. How w

ould you determine which solution is which?
Chemistry
1 answer:
quester [9]2 years ago
5 0

In a saturated solution, extra solid X would remain solid, dissolve in an unsaturated solution, and crystallize in a supersaturated one.

A solution is said to be saturated when there is a maximum amount of solute present that has been dissolved in the solvent. As a result, the system is in an equilibrium between the dissolved and undissolved solutes: A solution is considered to be unsaturated if the solute concentration is less than the equilibrium solubility. A supersaturated solution is one that has more solute than is necessary to generate a saturated solution at a given temperature.

Learn more about Supersaturated here-

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Black_prince [1.1K]

Answer:

Theoretical yield: 2.75g of paranitroaniline

Percentage yield: 54.5%

Explanation:

In strong-acid medium, acetanilide (Molar mass: 135.16g/mol) reacts producing para-nitroaniline (138.12g/mol) in a 1/1 reaction.

Theoretical yield of para-nitroaniline is the mass produced assuming a yield of 100%. That is:

2.7g acetanilide × (1mol / 135.16g) = 0.020 moles of acetanilide.

Assuming a yield of 100% are 0.020 moles of paranitroaniline. Theoretical yield is:

0.020 moles × (138.12g / mol) =

<h3>Theoretical yield: 2.75g of paranitroaniline</h3><h3 />

Percentage yield is:

(Actual yield / theoretical yield) × 100

Actual yield was 1.5g and percentage yield will be:

Percentage yield: (1.5g / 2.75g) × 100

<h3>Percentage yield: 54.5%</h3>

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3 years ago
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<h3><u>Answer;</u></h3>

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<h3><u>Explanation;</u></h3>
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