Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Answer:
A) chlorine
Explanation:
To solve this question we can use:
PV = nRT
In order to solve the moles of the gas. With the moles and the mass we can find the molar mass of the gas to have an idea of its identy:
PV = nRT
PV / RT = n
<em>Where P is pressure: 603mmHg * (1atm / 760mmHg) = 0.7934atm</em>
<em>V = 100mL = 0.100L</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 14°C + 273.15 = 287.15K</em>
0.7934atm*0.100L / 0.082atmL/molK*287.15K = n
3.37x10⁻³ moles of the gas
In 0.239g. The molar mass is:
0.239g / 3.37x10⁻³ moles = 70.9g/mol
The gas with this molar mass is Chlorine, Cl₂:
<h3>A) chlorine
</h3><h3 />
Answer:
The answer is
<h2>0.15 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of object = 13.57 g
volume = 89.6 mL
The density is
We have the final answer as
<h3>0.15 g/mL</h3>
Hope this helps you
A and d is physical, b and c is chemical
