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kolezko [41]
3 years ago
6

Based on the research of Albert Einstein, what change would most likely result in stopping the emission of electrons from this m

etal?
an increase in the intensity of the light
a decrease in the intensity of the light
the use of light that has a higher frequency
the use of light that has a lower frequency
Chemistry
2 answers:
saul85 [17]3 years ago
7 0
The use of light that has a lower frequency
ANEK [815]3 years ago
5 0

Answer:  The use of light that has a lower frequency

Explanation:  In order to stop the emission of electrons from the metal, the light used should be of lower frequency so that it wont be able to strike off the metal atom as effectively as it could.

When we use the light of lower frequency, the kinetic energy of the light decreases and thus it wont be able to emit much of the electrons from the metal surface.

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How many grams are in 2.3 x 10-4 moles of calcium phosphate,<br> Ca3(PO3)2?
scZoUnD [109]

Answer:

7136900g or 7136 kg

 

Explanation:

5 0
3 years ago
A gas with a volume of 500. mL at 75°C is heated to 225 °C. What is the new volume of the gas?
mihalych1998 [28]
Using v1/t1=v2/t2
v1=500
v2=?
t1=75=368k
t2=225=498
500/368=v2/498
1.4x498=v2
v2=697.2ml
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3 years ago
For each pair of gases, select one that most likely has the highest rate of effusion. Use the periodic table if necessary
brilliants [131]
You will do the highest one i think
4 0
3 years ago
Read 2 more answers
A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar
Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The  \  mass  \  of  \  the substance}{The   \  Molar  \   Mass   \  of  \   the   \  substance}

Therefore, we have;

The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of  formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³  ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

8 0
2 years ago
The half life of plutonium-239 (239pu, pu-239) is 24,100 years. How much plutonium will remain after 1000 years if the initial a
Anestetic [448]

The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g

The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

n=1000/24100=0.0414

So Mr=5x(1/2)^1=2.5 g

The mass remaining is 2.5 g

  • The half life is the time in which the concentration of a substance decreases to half of the initial value.

Learn more about half life at:

brainly.com/question/24710827

#SPJ4

8 0
1 year ago
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