You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Test them
1 doesn't work, so cross out A and D
2 doesn't work cross out B
answer is C
Answer:
a= 20 b= 160 c= 90
Step-by-step explanation:
Based on how 20 is the angle as you can see by the arrow I made the assumption that a is 20 degrees and for c my estimated guess is 90 because if you imagine how many of the 20 degree angle can fit there you get around 80-90 so I made the guess it was option C. I am sorry if this doesn't make sense I tired to understand it I hope you get the answer right. Also enjoy the rest of your day!
The answer to the question is 596.39
