If you have to write<span> the chemical </span>formula<span> of a simple, binary ionic compound given the name of the compound, you follow a set of three steps. Let's go through them using magnesium chloride as an example. </span>Write<span> the symbols for the cation and the anion: Mg and Cl. Determine the charge on the cation and anion.</span>
Explanation:
Lift the kitten's tail. The opening just under the tail is the anus. Below the anus is the genital opening which is round in males and is a vertical slit in females. In kittens of similar size, the distance between the anus and the genital opening is greater in the male than the female.
Answer:
C) a halohydrin
Explanation:
In organic chemistry, a halohydrin is a compound whereby halogen and hydroxyl functional groups are bonded to adjacent carbon atoms in the molecule. Halohydrins are formed from alkenes such as cyclohexene in this case.
NBS is a very suitable alternative to Br2 in the synthesis of a halohydrin. Recall that the reactive intermediate when bromine reacts with an alkene is the brominium ion which is a three atom ring ion. If excess water is used as the solvent, then the water attacks the brominium ion to yield the product halohaydrin with trans a trans stereochemistry.
Answer:
108.76 amu is the mass of 109Ag
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 109Ag:
% = 51.82 %
Mass = x amu
For second isotope, 107Ag:
% = 100 - x
= 100 - 51.82 % = 48.18 %
Mass = 106.905 amu
Given, Average Mass = 107.868 amu
Thus,
Solving for x, we get that:
x = 108.76 amu
<u>108.76 amu is the mass of 109Ag</u>
The given complex ion is as follow,
[Ru (CN) (CO)₄]⁻
Where;
[ ] = Coordination Sphere
Ru = Central Metal Atom = <span>Ruthenium
CN = Cyanide Ligand
CO = Carbonyl Ligand
The charge on Ru is calculated as follow,
Ru + (CN) + (CO)</span>₄ = -1
Where;
-1 = overall charge on sphere
0 = Charge on neutral CO
-1 = Charge on CN
So, Putting values,
Ru + (-1) + (0)₄ = -1
Ru - 1 + 0 = -1
Ru - 1 = -1
Ru = -1 + 1
Ru = 0
Result:
<span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
