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lutik1710 [3]
3 years ago
6

Write the balanced equation for the breakdown of hydrogen peroxide? PLEASE HELP! WILL MEDAL! This chapter is so confusing for me

. Thanks so much!
Chemistry
2 answers:
Deffense [45]3 years ago
4 0
Hydrogen peroxide is another way of dihydrogen dioxide

So,

H2 + O2 = H2O2 or 1 hydrogen per 1 oxygen
MariettaO [177]3 years ago
3 0
The Breakdown off Hydrogen peroxide Using Catalase Introduction Enzymes such as Catalase are protein molecules, which are found in living cells. They are used to speed up specific reaction within the cell. They are all very specific as each enzyme just performs one particular reaction.

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Which living thing would u expect to find in a swamp
stich3 [128]

Alligators, Crocodiles, Anacondas, Beavers, Fish , Frogs and MANY more.



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6 0
3 years ago
A snowflake contains 2.1 10^18 molecules of water. How many moles of water does it contain?
IgorC [24]

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divide the # of molecules by avogadros number and get 3.48 x 10^-6

Explanation:

6 0
2 years ago
Which of the following statements correctly describes the relationship between volume and temperature( moles and pressure of gas
lorasvet [3.4K]

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pressure of gas are constant describe the relationship between moles and temprature

6 0
3 years ago
The equilibrium: 2 NO2(g) \Longleftrightarrow⇔ N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar
Sergeeva-Olga [200]

Answer:

  • Initial: forward rate > reverse rate
  • Equilibrium: forward rate = reverse rate

Explanation:

2NO₂(g) → N₂O₄(g)   Kc=4.7

The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

7 0
3 years ago
A student mixes a solution containing 10.0 g bacl2 (m = 208.2) with a solution containing 10.0 g na2so4 (m = 142.1) and obtains
professor190 [17]
The balanced equation for the above reaction is as follows;
Na₂SO₄ + BaCl₂ --> BaSO₄ + 2NaCl
Na₂SO₄ reacts with BaCl₂ in the molar ratio 1:1
Number of Na₂SO₄ moles - 10.0 g / 142.1 g/mol = 0.0704 mol
Number of BaCl₂ moles - 10.0 g / 208.2 g/mol = 0.0480 mol
this means that 0.0480 mol of each reactant is used up, BaCl₂ is the limiting reactant and Na₂SO₄ has been provided in excess. 
stoichiometry of BaCl₂ to BaSO₄ is 1:1
number of BaSO₄ moles formed - 0.0480 mol
Mass of BaSO₄ - 0.0480 mol x 233.2 g/mol = 11.2 g
theoretical yield is 11.2 g but the actual yield is 12.0 g
the actual product maybe more than the theoretical yield of the product as the measured mass of the actual yield might contain impurities. 
percent yield - 12.0 g/ 11.2 g x 100% = 107% 
this is due to impurities present in the product or product could be wet.
4 0
3 years ago
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