The balanced chemical reaction would be
<span>4Fe(s) + 3O2(g) ---> 2Fe2O3(s)
We are given the amount of Fe to be used in the reaction. We use this as the starting point for the calculations. We do as follows:
25.9 g Fe (1 mol / 55.85 g) ( 2 mol Fe2O3 / 1 mol Fe ) (159.69 g / mol ) = 262.48 g Fe2O3 produced</span>
Answer:
1,42M
Explanation:
Molar concentration is given in moles of solute per liter o solution. Assuming you have 100g of solution:
10g KCl × (1mol / 74,55g) = <em>0,134 moles of KCl</em>
As you have 100g of solution:
100g × (1mL / 1,06g) × (1L / 1000mL) = <em>0,0943L</em>
<em> </em>
That means molar concentration is:
0,134 moles of KCl / 0,0943L = <em>1,42M</em>
<em></em>
I hope it helps!
The choices for this question are N2, O2 and H2O. I believe the closest correct answer would be N2. H2O would have the strongest one as it is capable of hydrogen bonding which is one strong intermolecular force. To compare oxygen and nitrogen, we look at properties of both substances. Oxygen would have a higher boiling point than nitrogen which means oxygen would require more energy to allow phase transition so it should have a stronger force than nitrogen. Thus, nitrogen would have the weakest intermolecular force.
The required volume of water to make the dilute solution of 0.5 M is 188 mL.
<h3>How do we calculate the required volume?</h3>
Required volume of water to dilute the stock solution will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of stock solution.
- M₂ & V₂ are the molarity and volume of dilute solution.
On putting values from the question to the above equation, we get
V₂ = (2)(47) / (0.5) = 188mL
Hence required volume of water is 188 mL.
To know more about volume & concentration, visit the below link:
brainly.com/question/7208546
#SPJ1
Let's eliminate some options.
Option A: quadruple bonds will most likely not occur between two carbon atoms. so option A is out.
Option B: One double bond with oxygen and two single bonds with hydrogen atoms will give all atoms the "noble gas" or "octet" configuration they desire. Option B is true.
Option C: Carbon is most likely not large enough to have more than eight valence electrons (hypervalent), so option C is out.
Option D: One carbon only has four valence electrons to donate, so the same problem exists as in option C, and the carbon atom will not achieve hypervalence. Option D is out.
Therefore, option B is correct.