Answer:
4057.85 g/mol
Explanation:
Hello, the numerical procedure is shown in the attached file.
- In this case, since we don't have the density of the protein, we must assume that the volume of the solution is solely given by the benzene's volume, in order to obtain the moles of the solute (protein).
-Van't Hoff factor is assumed to be one.
Best regards.
N<span>et ionic equation for ammonia and phosphoric acid</span> is
3 NH4OH + H3PO4 >> (NH4)3PO4 + 3 H2O
hope this helps
Answer:
i think it is a Cobrotoxin
Answer:
- <em>The maximum amount of copper allowed in 100 g of water is </em><u><em>0.00013 g</em></u>
Explanation:
To find the maximum amount of copper (in grams) allowed in 100 g of water use the maximum amount ratio (1.3 mg / kg) and set a proportion with the unknown amount of copper (x) and the amount of water (100 g):
First, convert 100 g of water to kg: 100 g × 1 kg / 1000 g = 0.1 kg.
Now, set the proportion:
- 1.3 mg Cu / 1 Kg H₂O = x / 0.1 kg H₂O
Solve for x:
- x = 0.1 kg H₂O × 1.3 mg Cu / 1 kg H₂O = 0.13 mg Cu
Convert mg to grams:
- 0.13 mg × 1 g / 1,000 mg = 0.00013 g
Answer: 0.00013 g of copper.
<h3>
Answer:</h3>
2.51 mol Cu
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1.51 × 10²⁴ atoms Cu
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})](https://tex.z-dn.net/?f=%5Cdisplaystyle%201.51%20%5Ccdot%2010%5E%7B24%7D%20%5C%20atoms%20%5C%20Cu%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Cu%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Cu%7D%29)
- Multiply/Divide:
![\displaystyle 2.50747 \ mol \ Cu](https://tex.z-dn.net/?f=%5Cdisplaystyle%202.50747%20%5C%20mol%20%5C%20Cu)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2.50747 mol Cu ≈ 2.51 mol Cu