<span>These hydrocarbons are many and this depends on the phase diagram of the substance. In a phase diagram, the phase
can be determined by looking at a certain temperature and pressure. For this case, at a temperature of 20 degrees Celsius and at 1 atmosphere.</span>
Answer:
nuclear vision provides energy for nuclear power and drives the explosion of nuclear weapons both uses are possible because certain substances called nuclear fuels undergo visions when struck by fishing neutrons and turned into emit neutrons when they break apart
Explanation:
I remember taking this test and seen this on the test and it was correct
The given question is incomplete. The complete question is
If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.
Answer: The equilibrium concentration of
is 0.498 M
Explanation:
Initial concentration of
= 1.0 M
The given balanced equilibrium reaction is,

initial (1.0) M 0 0
At eqm (1.0-2x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[H_2]\times [I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
Now put all the given values in this expression, we get :

By solving we get :

Thus the equilibrium concentration of
is 0.498 M
Answer:
Option "C" is the correct answer to the following question.
Explanation:
Given:
Pressure in an automobile tire (P) = 1.88 atm
Temperature (K) = 25°C = 273 + 25 = 298 Kelvin
New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin
Find:
New pressure in an automobile tire (P1) = ?
Computation:

New pressure in an automobile tire (P1) = 1.9557
New pressure in an automobile tire (P1) = 1.96 (Approx)
Answer:
The answer to your question is: letter D
Explanation:
Data
Isotope mass 1 = 54 amu
Isotope mass 2 = 56 amu
Atomic weight = 54.37 amu
Percent abundance of isotope 2 = ? = X
Percent abundance of isotope 1 = 1 - x
Formula
Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)
Process
Place the data in the formula and solve for x.
54.37 = 54( 1 - x) + 56x
54.37 = 54 - 54x + 56x
54.37 - 54 = -54x + 56x
0.37 = 2x
x = 0.37 / 2
x = 0.185
To find the percent multiply by 100
x = 0.185 x 100
x = 18.5 % = Mass of isotope 2
Mass of isotope 1 = 100 - 18.5 = 81.5 %