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andreev551 [17]
3 years ago
8

A student claims that she cannot identify the exact location of an electron. Which of the following explains if the student's cl

aim is correct or
incorrect? (1 point)

The claim is incorrect because a particle can have a known location at a given time.

The claim is correct because an electron is invisible and cannot be seen.

The claim is correct because we cannot determine the exact location of an electron at a given time.
The claim is incorrect because the exact position of matter is always visible or can be determined.
Chemistry
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

The claim is incorrect because the exact position of matter is always visible or can be determined.

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What types of hydrocarbons are usually liquid at room temperature?
marishachu [46]

<span>These hydrocarbons are many and this depends on the phase diagram of the substance. In a phase diagram, the phase can be determined by looking at a certain temperature and pressure. For this case, at a temperature of 20 degrees Celsius and at 1 atmosphere.</span>

8 0
3 years ago
Why is nuclear fision relevant?
Iteru [2.4K]

Answer:

nuclear vision provides energy for nuclear power and drives the explosion of nuclear weapons both uses are possible because certain substances called nuclear fuels undergo visions when struck by fishing neutrons and turned into emit neutrons when they break apart

Explanation:

I remember taking this test and seen this on the test and it was correct

5 0
4 years ago
If 1.0 M HIM HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equili
sattari [20]

The given question is incomplete. The complete question is

If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.

Answer: The equilibrium concentration of H_2 is 0.498 M

Explanation:

Initial concentration of HI = 1.0 M

The given balanced equilibrium reaction is,

                         2HI(g)\rightarrow H_2(g)+I_2(g)

initial                  (1.0) M                  0              0

At eqm               (1.0-2x) M               (x) M      (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]\times [I_2]}{[HI]^2}

Now put all the given values in this expression, we get :

62=\frac{(x)^2}{1.0-2x}

By solving we get :

x=0.498M

Thus the equilibrium concentration of H_2 is 0.498 M

6 0
3 years ago
PLEASE HELP!!!!!!!!!
KonstantinChe [14]

Answer:

Option "C" is the correct answer to the following question.

Explanation:

Given:

Pressure in an automobile tire (P) = 1.88 atm

Temperature (K) = 25°C = 273 + 25 = 298 Kelvin

New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin

Find:

New pressure in an automobile tire (P1) = ?

Computation:

\frac{P}{K}= \frac{P1}{K1} \\\\\frac{1.88}{298}= \frac{P1}{310}\\\\1.9557

New pressure in an automobile tire (P1) = 1.9557

New pressure in an automobile tire (P1) = 1.96 (Approx)

5 0
3 years ago
A hypothetical element has two main isotopes. One has a mass of 54 amu and the other has a mass of 56 amu. If the atomic weight
castortr0y [4]

Answer:

The answer to your question is: letter D

Explanation:

Data

Isotope mass 1 = 54 amu

Isotope mass 2 = 56 amu

Atomic weight = 54.37 amu

Percent abundance of isotope 2 = ? = X

Percent abundance of isotope 1 = 1 - x

Formula

Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)

Process

Place the data in the formula and solve for x.

54.37 = 54( 1 - x) + 56x

54.37 = 54 - 54x + 56x

54.37 - 54 = -54x + 56x

0.37 = 2x

x = 0.37 / 2

x = 0.185

To find the percent multiply by 100

x = 0.185 x 100

x = 18.5 % = Mass of isotope 2

Mass of isotope 1 = 100 - 18.5 = 81.5 %

8 0
4 years ago
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