(3x²-2x-4)(2x²+x-3)=3x²(2x²+x-3)-2x(2x²+x-3)-4(2x²+x-3)=
=6x⁴+3x³-9x²-(4x³+2x²-6x)-(8x²+4x-12)=
=6x⁴+3x³-9x²-4x³-2x²+6x-8x²-4x+12=
=6x⁴-x³-x²+2x+12
Answer:
x² + 1
or if we suppose
x² + 1 = 0 the n we get value of x
x = ±1
Step-by-step explanation:
x²+x/x (cancel out both x/x we get)
x² + 1
Let suppose
x²+x/x = 0
x² + 1 =0
x²=-1
taking square root on both side we get
x = ±1
:)
Answer:
answer is a
Step-by-step explanation:
thank me later:)
Answer: b is 6
Step-by-step explanation:
Set the proportions up and solve for b
b. 3
---- = ------
10. 5
I think the answer is 12a-48