Very simple. You just use the vectors as normal numbers, and multiply the coordinates with 2 and 4 like this:
2*u = 2* (2,4) = (4,8)
4*w = 4* (-1,3) = (-4,12)
(4,8) - (-4,12) = (8,-4)
So the vector has the coordinates (8,-4)
-320<t because the temperature has to be greater then -320
5x²+y²=3
by implicit differentiation we shall have:
10x+2yy'=0
the second derivative will be:
10+2y"=0
2y"=-10
y"=-5
Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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