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3 years ago

What is the value of y in the solution of the system of equations?

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

baki baki ni ore nani wo kokoro wo da yo kunagona no kudake nani wo?

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Mr solomon can run 2 1/2 in 2 hours. how many miles can he run in 6 hour<br><br> PLZ HELP!!

Marat540 [252]

Answer:

7 1/2

Step-by-step explanation:

2 1/2 times 3 is 7 1/2

6 0

2 years ago

Read 2 more answers

Lily has a stamp collection .she has 54 more U.S stamps than foreign stamps . she has 652 stamps in all.

NISA [10]

Answer:

foreign stamps = 299

US stamps = 353

Step-by-step explanation:

Let number of foreign stamps be x.

Given she has 54 more U.S stamps than foreign , US stamps = x +54

Total stamps = US + Foreign

652 = x + 54 + x

652 - 54 = 2x

598 = 2x

x = 299

7 0

3 years ago

The diagram shows a right-angled triangle.

Alexus [3.1K]

Step-by-step explanation:

there is no diagram so I'm just going to guess this however

sin x = 6/9

sin x = 2/3

sin x = 0.67

x = sin inverse of 0.67

x = 42.1

8 0

3 years ago

Please help with the attached question. Thanks

Mademuasel [1]

Answer:

Choice A) $F(x) = 3\sqrt{x + 1}$ .

Step-by-step explanation:

What are the changes that would bring $G(x)$ to $F(x)$ ?

Translate $G(x)$ to the left by $1$ unit, and
Stretch $G(x)$ vertically (by a factor greater than $1$ .)

$G(x) = \sqrt{x}$ . The choices of $F(x)$ listed here are related to $G(x)$ :

Choice A) $F(x) = 3\;G(x+1)$ ;
Choice B) $F(x) = 3\;G(x-1)$ ;
Choice C) $F(x) = -3\;G(x+1)$ ;
Choice D) $F(x) = -3\;G(x-1)$ .

The expression in the braces (for example $x$ as in $G(x)$ ) is the independent variable.

To shift a function on a cartesian plane to the left by $a$ units, add $a$ to its independent variable. Think about how $(x-a)$ , which is to the left of $x$ , will yield the same function value.

Conversely, to shift a function on a cartesian plane to the right by $a$ units, subtract $a$ from its independent variable.

For example, $G(x+1)$ is $1$ unit to the left of $G(x)$ . Conversely, $G(x-1)$ is $1$ unit to the right of $G(x)$ . The new function is to the left of $G(x)$ . Meaning that $F(x)$ should should add $1$ to (rather than subtract $1$ from) the independent variable of $G(x)$ . That rules out choice B) and D).

Multiplying a function by a number that is greater than one will stretch its graph vertically.
Multiplying a function by a number that is between zero and one will compress its graph vertically.
Multiplying a function by a number that is between $-1$ and zero will flip its graph about the $x$ -axis. Doing so will also compress the graph vertically.
Multiplying a function by a number that is less than $-1$ will flip its graph about the $x$ -axis. Doing so will also stretch the graph vertically.

The graph of $G(x)$ is stretched vertically. However, similarly to the graph of this graph $G(x)$ , the graph of $F(x)$ increases as $x$ increases. In other words, the graph of $G(x)$ isn't flipped about the $x$ -axis. $G(x)$ should have been multiplied by a number that is greater than one. That rules out choice C) and D).

Overall, only choice A) meets the requirements.

Since the plot in the question also came with a couple of gridlines, see if the points $(x, y)$ 's that are on the graph of $F(x)$ fit into the expression $y = F(x) = 3\sqrt{x - 1}$ .