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3 years ago

What is the value of y in the solution of the system of equations?

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

baki baki ni ore nani wo kokoro wo da yo kunagona no kudake nani wo?

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Please help it’s geometry! I’ll make brainliest

expeople1 [14]

GX is the angle bisector. Answer is C

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3 years ago

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Adi is t inches shorter than sunnee sunnee is n inches taller which expression repesent adies hight in inches

kramer

Answer:

adi's height = n-t inches

Step-by-step explanation:

from this question

we have Adi to be t inches shorter than sunnee.

sunnee's height = n inches tall

to get adis height, we have to subtract the height difference t from sunnee's height.

the height difference is how many inches by which Adi is shorter = t

adies height = sunnee's height, n - difference in height, t

= (n-t) inches

this expression represents adis height in inches .

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3 years ago

Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$

$n(1-p)=600*(1-0.4)=360 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=600*0.4=240$

$\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12$

And then $X \sim N (\mu = 240, \sigma= 12)$

And we are interested on the following probability:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

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3 years ago

Evaluate the expression (ab)2 for a = 2 and b = 5. 100 50 20 625

kakasveta [241]

(ab)2

((2)(5.1005020625)2=?

((2)(5.1005020625)2=20.402

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3 years ago

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Find the range for the given domain: {-2, -1, and 0} and the function is y= 3x^2

likoan [24]

Answer:

{0, 3, 12}

Step-by-step explanation:

Put the domain values in the function and evaluate. The result is the range values.

y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}

For the given domain, the range is {0, 3, 12}.

_____

Additional comment

Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.

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3 years ago