Answer:
The graph in the attached figure
Step-by-step explanation:
we have

This is a linear equation (the graph is a line)
To identify the graph find out the intercepts
<u><em>Find out the y-intercept</em></u>
The y-intercept is the value of y when the value of x is equal to zero
For x=0

The y-intercept is the point (0,-4)
<u><em>Find out the x-intercept</em></u>
The x-intercept is the value of x when the value of y is equal to zero
For y=0



The x-intercept is the point (5.33,0)
therefore
The graph in the attached figure
Answer:
b. g(x) = ƒ(3x)
Step-by-step explanation:
We can use the graph to find the transformation which has been performed to obtain g.
g(x) is more stretched than x which means the function values are multiplied by some integer to obtain g(x). <u>This eliminates the options a and d.</u>
Now to check which factor is used to transform the function f(x) we can divide the x-coordinates of the points of new and old function.
So,
6/2 = 3
-6/-2 = 3
The function is stretched by a factor of 3.
Hence, the correct answer is:
b. g(x) = ƒ(3x) ..
0.75 because 100cm = 1m so you just move the decimal to the right by 2
Responda:
Preço = $ 400
Explicação passo a passo:
Dado que:
Primeira opção :
Pagamento em 5 investimento igual
Segunda opçao :
Pagamento feito em 8 iguais. Investimento
O preço por parcela do primeiro investimento é 30 a mais do que cada um do segundo
Deixe o preço do telefone = p
Valor por prestação = x
Segunda parcela:
Preço = 8x
Primeiro :
Valor por parcela = x + 30
P = 5 (x + 30)
Preço = 5x + 150
Portanto, igualando as duas equações:
8x = 5x + 150
8x - 3x = 150
5x = 150
x = $ 50
Usando qualquer das equações de preço:
Preço = 8x
Preço = 8 * 50
Preço do telefone = $ 400
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)
Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0).
The formula for slope is <u>Y1-Y2</u>
X1-X2
We can break this down with our two points (center and tangent)
(0,0) and (-4,-5)
(X1,Y1) and (X2,Y2)
therefore, we will put the equation as such
<u>0-(-5)= 5</u> = <em> </em><u><em>5</em></u>
0-(-4)= 4 <em> 4</em>
<em>this is our slope from the center to the point of tangency.</em>
We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to.
Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> = <u>-5</u> = <u>-4</u><u>
</u>4 4 5
Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.
Slope-int y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept ( the point where x=0, or where its on the y axis)
now we plug things in
(-4,-5) is our point,
<u>-4</u> is our slope
5
-5=<u>-4</u>(-4)+b After we plug things in, solve for b
5
-5= 3.2+b
-1.8= b or b= <u />1 <u>4</u>
5
Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u> = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u> 5
<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em> This is the equation of the tangent line</em><u>
</u><em> 5 5</em>
Hope that helped