The amount of moles in 3.34 x10³⁴ formula unit of Cu(OH)₂ is 5.55 × 10¹⁰ moles
<u><em>calculation</em></u>
The amount of moles is calculated using the Avogadro's law constant
That is 1 moles = 6.02 × 10²³ formula units
? moles = 3.34 × 10³⁴ formula units
<em>by cross multiplication</em>
= {1 mole ×3.34 ×10³⁴ formula units ] / 6.02 × 10²³ formula units} = 5.55 ×10¹⁰ moles
IT IS D FOCAL POINT
P.S. im in middle school not trying to brag
Fault block mountains folded mountains
In 1869, just five years after John Newlands put forward his law of octaves, a Russian chemist called Dmitri Mendeleev published a periodic table. Mendeleev also arranged the elements known at the time in order of relative atomic mass, but he did some other things that made his table much more successful.
i hope this helps in some way!
To be able to calculate the number of moles for this problem, for simplicity, we assume that it is an ideal gas. We use the equation PV = nRT. We do as follows:
PV = nRT
n = PV / RT
n = 1(100000) / 0.08206 (27 + 273.15)
n = 4060.04 mol
