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navik [9.2K]
3 years ago
15

Consider the following reaction:

Chemistry
1 answer:
Goshia [24]3 years ago
3 0

Answer:

2.01

Explanation:

First, let's convert grams to moles

(Na) 22.99 + (F) 18.998 = 41.988

Every mole of NaF is  41.988 grams

21/41.988 = 0.500143 moles of NaF

For every Cr+3, we will need 2 NaF, so Cr+3 will be half of NaF

0.500143/2 = 0.250071

molarity = moles/liters

0.250071/0.125 = 2.0057 M

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You need a 20% alcohol solution. on hand, you have a 240 ml of a 15% alcohol mixture. you also have 40% alcohol mixture. how muc
juin [17]
0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
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3 years ago
How many grams are in 0.220 mol of Ne?
yawa3891 [41]

Answer:

Mass = 4.44 g

Explanation:

Given data:

Number of moles of Ne = 0.220 mol

Mass in gram = ?

Solution:

Formula:

Number of moles = mass/ molar mass

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by putting values,

0.220 mol = mass/ 20.2 g/mol

Mass = 0.220 mol × 20.2 g/mol

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5 0
3 years ago
Use bond energies to calculate ΔHrxn Δ H r x n for the reaction. 2H2(g)+O2(g)→2H2O(g) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( g )
Olenka [21]

Answer:

\large \boxed{\text{-486 kJ}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                      2H₂   +   O₂ ⟶ 2H-O-H

Bonds:          2H-H    1O=O       4H-O

D/kJ·mol⁻¹:     436      498          464

\begin{array}{rcl}\Delta H & = & \sum{mD_{\text{reactants}}} - \sum{nD_{\text{products}}}\\& = & 2 \times 436 +1 \times 498 - 4 \times 464\\&=& 1370 - 1856\\&=&\textbf{-486 kJ}\\\end{array}\\\text{The enthalpy of reaction is $\large \boxed{\textbf{-486 kJ}}$}.

3 0
3 years ago
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