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valina [46]
3 years ago
15

A 100kg sumo wrestler named Bob is doing his daily run. He runs at a velocity of 8m/s. After the run Bob stops for a rest, and s

its at the river.
What is Bob's momentum will resting at the river?
Question 10 options:
800 kgm/s
800 kgm/s^s
0 kgm/s
12.5 kgm/s^2
Chemistry
1 answer:
Elza [17]3 years ago
5 0

Answer:

0 kgm/s

Explanation:

The momentum of Bob while resting at the river is 0 kgm/s.

This is because the momentum of any object at rest is 0.

 Momentum is the quantity of motion a body contains. It is mathematically expressed as;

  Momentum  = m x v

m is the mass

v is the velocity

 So at rest, the velocity of a body is 0m/s and therefore, the momentum is O

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Air trapped in a cylinder fitted with a piston occupies 145.7 mL at 1.08 atm pressure. What is the new volume when the piston is
Anon25 [30]

The new volume of air trapper in the cylinder is determined as 116.56 mL.

<h3>New volume of air in the cylinder</h3>

The volume of air trapper in the cylinder is determined from Boyle's law;

P₁V₁ = P₂V₂

where;

  • P₁ is initial pressure = 1.08 atm
  • V₁ is initial volume = 145.7 mL
  • P₂ is new pressure = 1.25 x 1.08 atm = 1.35 atm
  • V₂ is new volume = ?

V₂ = (P₁V₁)/P₂

V₂ = (1.08 x 145.7)/1.35

V₂ = 116.56 mL

Thus, the new volume of air trapper in the cylinder is determined as 116.56 mL.

Learn more about volume here: brainly.com/question/1972490

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Answer:

The smallest ballon is the ballon X

Explanation:

It is possible to answer this question by using Graham's law:

\frac{v_1}{v_2} =\sqrt{\frac{MW_2}{MW_1}}

Where v is the speed of effusion and MW is molar weight of each compound.

This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>

<em></em>

I hope it helps!

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