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frutty [35]
3 years ago
6

I am named after the Russian scientist who organized the periodic table by atomic mass. Who am I?

Chemistry
2 answers:
solmaris [256]3 years ago
7 0

Answer:

organesson

Explanation:

the element 118th symbol Og

Basile [38]3 years ago
7 0

Answer:Dmitri Mendeleev

Explanation:

In 1869, Russian chemist Dmitri Mendeleev created the framework that became the modern periodic table, leaving gaps for elements that were yet to be discovered. While arranging the elements according to their atomic weight, if he found that they did not fit into the group he would rearrange them.

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likoan [24]
The correct answer is C. Hope it helped!!!!!
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Which of the following is the major product in the electrophilic addition of HCl to (3S)-2,3-dimethylpent-1-ene?
kvv77 [185]

Answer:

(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.

Explanation:

Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.

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In the second step, Cl^{-} adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)

So, option (d) is correct.

5 0
3 years ago
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inna [77]

Answer:

C

Explanation:

<em>The </em><em>specific</em><em> </em><em>heat </em><em>capacity</em><em>=</em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>in </em><em>joule/</em><em>mass×</em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in </em><em>temperature</em>

<em>from </em><em>this </em><em>question</em><em> </em><em>the </em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>is </em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>,</em><em>the </em><em>mass </em><em>is </em><em>2</em><em>0</em><em>0</em><em>0</em><em> </em><em>and </em><em>the </em><em>change </em><em>in </em><em>temperature</em><em> </em><em>is </em><em>5</em><em>0</em><em>-</em><em>3</em><em>0</em>

<em>which </em><em>is </em><em>2</em><em>0</em>

<em>therefore</em>

<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>2</em><em>0</em><em>0</em><em>0</em><em>×</em><em>2</em><em>0</em>

<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>4</em><em>0</em><em>0</em><em>0</em><em>0</em>

<em>c=</em><em>1</em><em>.</em><em>8</em><em>8</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

3 0
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Furkat [3]
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