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2 years ago

Can someone please help me asap?

Mathematics

1 answer:

pashok25 [27]2 years ago

3 0

find the area the get the premiraterStep-by-step explanation:add

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32 and 2.56 what is the unit rate

Serggg [28]

12.5

I hope this helped.

5 0

2 years ago

A rhombus is cut along the diagonals to make four triangles. Which three statements are correct for any rhombus? 1) All four tri

Nikolay [14]

Answer:

1). All four triangles are right-angled.

3.) All four triangles are congruent.

4) Area of a rhombus = 4 x area of one triangle.

Step-by-step explanation:

If a rhombus is cut into four triangles using diagonals, the three statements that would apply to any rhombus would be that 'all those four triangles would be right-angled,' 'the triangles would be congruent to one another,' and 'area of one triangle * 4 would be equal to the area of the rhombus.'

As we know, the diagonals bisect one another in a rhombus at 90° and the angles opposite to one another are equal. This proves that all four triangles constructed through the diagonals would be ≅ through SSS congruency and perpendicular to one another because the corresponding edges of the congruent triangles are also ≅ . Since the rhombus is divided into four equal parts, the area of one triangle into four would be equals to the area of the rhombus. Thus, options 1, 3, and 4 are the correct answers.

8 0

2 years ago

What is the factor of 3x2-9x-12? pleaseeee help me guys !!

8090 [49]

Answer:3x² - 9x - 12 =

3(x² - 3x - 4) =

3(x² + x - 4x - 4) =

3(x(x+1)-4(x+1)) =

3(x+1)(x-4)

Step-by-step explanation:

8 0

3 years ago

URGENT graph the image of the given triangle after the transformation that has the rule (x, y) 》(x, -y)

crimeas [40]

Answer:

See Below

Step-by-step explanation:

That rule is a transformation across the x-axys.

Assigne a letter to each point:

A = (2, 7) => A' = (2, -7)

B = (-5, -2) => B' = (-5, 2)

C = (4, -3) => C' = (4, 3)

3 0

3 years ago

Read 2 more answers

the Hog's head pub decide to make mixture thst is 50% butterbeer. how much of an 80% butterbeer solution should mixed with 20 ga

evablogger [386]

There are 20 gallons of 20% butterbeer solution.
Assume there are x gallons of 80% solution.

So total amount of the solution will be (x+20) gallons
The final solution is 50%.

So, we can set up the equation as:

$0.2(20)+0.8(x)=0.5(x+20) \\ \\ 4+0.8x=0.5x+10 \\ \\ 0.8x-0.5x=10-4 \\ \\ 0.3x=6 x=20$ .

Thus, there will be 20 gallons of 80% butterbeer solution that is needed to be mixed with 20 gallons of 20% butterbeer solution.

4 0

2 years ago