1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OleMash [197]
3 years ago
15

Help please How many grams in 7.57 moles of Calcium Nitrate (Ca(NO3)2)

Chemistry
1 answer:
vfiekz [6]3 years ago
5 0
I believe it’s 164.0878 grams
You might be interested in
Why does argon exist in nature as individual argon atoms and chlorine exist in nature as 2 chlorine atoms covalently bonded toge
Katarina [22]

Answer:

Argon has 8 valence electrons and no extras, it does not require a bond in order to fill its shells, its satisfied by itself.

Chlorine is missing 1 Electron, if it connects with another Chlorine it will be satisfying both of their needs with a Covalent bond.

Explanation:

8 0
3 years ago
Please help....thanks :)
Naya [18.7K]

Answer: someone help me with my work its so  hard

Explanation:

6 0
3 years ago
There are some exceptions to the trends of first and successive ionization energies. For each of the following pairs, explain wh
NNADVOKAT [17]

Answer:

(b) IE₂ of Ga >  IE₂ of Ge

Explanation:

Electronic configuration of Ga is [Ar] 3d¹⁰4s²4p¹

Electronic configuration of Ge is [Ar] 3d¹⁰4s²4p²

After 1st ionisation , Ga  becomes [Ar] 3d¹⁰4s² and becomes stable . Its

2 nd ionisation requires higher amount of ionisation energy. In case of Ge , there are 2 electrons in outermost orbital so it becomes stable after ionisation of 2 electrons.

4 0
3 years ago
Read 2 more answers
Is a 3.3% solution dilute or concentrated?<br><br><br><br> Dilute<br><br><br><br> Concentrated
Arisa [49]

Answer:

Dilute

Explanation:

A concentrated solutions is a one which has relatively large amount of dissolved solute in the solution whereas a dilute solution is a one which has relatively lower concentration of dissolved solute.

In the given solution there is only 3.3% of solute. So, we can say that the given solution is a dilute solution. However, these terms are relative.

6 0
2 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
Other questions:
  • How many formula units make up 12.8 g of magnesium chloride (MgCl2)? Express the number of formula units numerically.
    7·1 answer
  • What do tissues combine to form?
    5·2 answers
  • What must happen for a liquid water to become water vapor ?
    9·1 answer
  • why do you think the partnership of rutherford a partical experiments, and bohr, a theoretical mathematician, was so succesful i
    10·1 answer
  • A layer of sandstone is found on top of a layer of shale. What most likely happened in this area?
    6·1 answer
  • 50 Points
    10·2 answers
  • The following electron configuration notation represents an atom of which element?
    15·2 answers
  • substance x reacts with sodium carbonate to form a gas . The gas turns lime water cloudy. What is substance K and which process
    12·2 answers
  • If you move at 50 meters in 10 seconds, what is your speed?
    14·1 answer
  • What are the spectator ions in the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!