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enot [183]
2 years ago
5

Which ball has the most energy?

Chemistry
2 answers:
Nikitich [7]2 years ago
5 0
A ball held at 3 meters. Option B.
tensa zangetsu [6.8K]2 years ago
5 0

A ball held at 3 metres

Explanation:

Because it is in motion.

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A common misconception people have is that sugar is energy and energy is sugar but you know better. Create a clear explanation t
Gnom [1K]

Answer:There are important differences between naturally occurring sugars, ... Understanding these differences can help you make choices that are better for your health. ... of energy, along with a bevy of vitamins, minerals, and phytonutrients. ... sugar substitutes, but many people find they have an unpleasant

Explanation:

7 0
3 years ago
What is the average velocity between 3.00 and 6.00 seconds?
diamong [38]
1)
average velocity:
(3,9)
(6,36)
average velocity=(36-9)m/(6-3) s=27m/3s=9 m/s

Answer: 9 m/s, east. 

2)
(12, 144)
(15,225)
average velocity=(225-144)m/(15-12)s=81 m/3s=27 m/s

Answer: 27 m/s,east. 
8 0
3 years ago
Read 2 more answers
What is the sum of the coefficients of the balanced equation for:
Marianna [84]

Answer:

3 Pb(NO3)2 + Al2(SO4)3 = 2 Al(NO3)3 + 3 PbSO4

Explanation:

I think your equation is incorrect? This is balanced and the sum of coefficients is 9.

5 0
2 years ago
An unknown substance is obtained by police. The forensics laboratory has
timurjin [86]

Answer:

70.0 %

Explanation:

Step 1: Given data

  • Mass of nitrogen (mN): 74.66 g
  • Mass of the compound (mNxOy): 250 g

Step 2: Calculate the mass of oxygen (mO) in the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

mNxOy = mN + mO

mO = mNxOy - mN

mO = 250 g - 74.66 g = 175 g

Step 3: Determine the percent composition of oxygen in the sample

We will use the following expression.

%O = mO / mNxOy × 100%

%O = 175 g / 250 g × 100% = 70.0 %

5 0
2 years ago
What is the quantity of carbon-14 in a bone after 17,190 years if the initial mass of C-14 is 0.300 grams and the half-life is 5
Licemer1 [7]

Answer:

A. 0.038 g.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.

<u><em>The integration law of a first order reaction is:</em></u>

<em>kt = ln [Ao]/[A]</em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = 17,190 years.

[Ao] is the initial concentration of carbon-14 = 0.300 g.

[A] is the remaining concentration of carbon-14 = ??? g.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(17,190 years) = ln (0.300 g)/[A]

2.08 =  ln (0.300 g)/[A]

Taking exponential for both sides:

8.0 = (0.300 g)/[A]

<em>∴ [A] = 0.0375 g ≅ 0.038 g</em>

4 0
3 years ago
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