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goldenfox [79]
3 years ago
5

The colour of light depends on it's wave length.Red light have a wave length in the order of 7.8*10 raise to power of -7metre, e

xpress this length in micrometres, nanometres and Angstrome
Chemistry
1 answer:
Arisa [49]3 years ago
8 0
That will be 0.78*10 raise to the power of -1 nanometers
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What is the formula for the binary ionic compound formed between<br> zinc and nitrogen.
Stolb23 [73]

Answer: Zinc nitride (Zn3N2) is an inorganic compound of zinc and nitrogen, usually obtained as (blue)grey crystals. It is a semiconductor. In pure form, it has the anti-bixbyite structure.

Chemical formula: Zn3N2

Space group: Ia-3, No. 206

EC Number: 215-207-3

Appearance: blue-gray cubic crystals

Explanation:

6 0
2 years ago
*multiple choice*
galben [10]

1.95  or 2  is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.

The correct answer is option b

Explanation:

Data given:

mass of KNO_{3} = 45.3 grams

volume = 0.225 litre

molarity =?

atomic mass of KNO3 = 101 grams/mole

molarity is calculated by using the formula:

molarity = \frac{number of moles}{volume of the solution}

first the number of moles present in the given mass is calculated as:

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles = \frac{45.3}{101}

0.44 moles of KNO3

Putting the values in the equation of molarity:

molarity = \frac{0.44}{0.225}

molarity = 1.95

It can be taken as 2.

The molarity of the potassium nitrate solution is 2.

7 0
3 years ago
a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

5 0
3 years ago
Which of the following reactions is not an example of an oxidation-reduction reaction? ( 2 points) Select one: a. H2 + F2yields
Kisachek [45]
Answer is: c. CuSO4 + 2NaOH yields Cu(OH)2 + Na2SO4.
Copper atom has oxidation number +2, sulfur atom oxidation number +6, oxygen has oxidation number-2, sodium has oxidation number +1 and hydrogen has +1 on both side of chemical reaction, so elements did not change their oxidation numbers.
4 0
3 years ago
Can you explain what makes Earth habitable using science vocabulary words system &amp; planetary geologist
finlep [7]
Earth is the right distance from the sun. It’s protected from harmful solar radiation by its magnetic field and the atmosphere keeps it warm. Earth contains the right chemical ingredients to sustain life such as H2O (water) and C (carbon)
7 0
3 years ago
Read 2 more answers
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