<h2>
Answer:</h2>
Hope it work for u
<h2>
Step-by-step explanation:</h2>
We can make points from the given figure as ,
1 point =(x1, y1)=(-2, -3)
2nd point =(x2, y2)= (0, -6)
3rd point = (x3, y3)=(2 , -9)
Now the equation of line is,
<h2>
Y=m X+ c where m is slope and c is constant </h2>
now two point formula of slope is ,
<h2>
m = y2-y1/x2-x1</h2>
putting points in it we get
m=(-6-(-3))/(0-(-2)
m=-3/2 is slope
Now to find C putt the value of m and 3rd point in equation of line we get
y3=m(x3)+c
-9=(-3/2)(2) +c
C= -9+3
C=-6 is value of c
Now at last putt the value of C and m in equation of line we get the required equation ,
<h2><u>
Y=(-3/2)X-6 </u>
Ans</h2>
Answer:
i would say that the rocket was in the air for 8 seconds and the highest it went in the air was 48
Step-by-step explanation:
Answer:
I think the answer is 2.. I'm sorry if its incorrect.
Step-by-step explanation:
Option D should be the right answer
An acute angle is any angle that is below 90 degrees, so 89 degrees is an ancute angle
