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skad [1K]
3 years ago
15

A 3220 kg truck is rolling down a frictionless 8.30° slope that is 22.0 m long. If its initial speed was 4.71 m/s, how fast is i

t going at the bottom? (Unit = m/s)​
Physics
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

9.2 m/s

Explanation:

v^2 = u^2 + 2as

u = 4.71

a= g * sin(8.30)

v= sqrt( 4.71^2 + 2 * 9.8* sin( 8.30 deg) * 22) = 9.2 m/s

Juli2301 [7.4K]3 years ago
6 0

Answer:

9.2

Explanation:

It is the correct answer (Acellus)

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