1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
4 years ago
6

We want to get a better, more concrete idea of the strength of the electric force. So imagine you could remove all the electrons

from 1 mL (1 cubic centimeter) of water. Dump the electrons on yourself, and put the electron-free nuclei (protons and neutrons) on the moon. Estimate how much force will there be between the positive and negative charges? (Of course you have to look up the earth-moon distance.) What fraction of your weight is that force? How many electrons do you have in 1 cc? Consider that virtually all the mass is given by protons and neutrons. Since the proton and the neutron have almost equal masses, and most atoms have equal numbers of protons and neutrons, so the water mass, divided by 2, is the mass of protons. Once you know the total mass of protons, divide by the mass of a single proton and you have the total number of protons. Knowing that, how many electrons do you then suppose you have?)

Physics
2 answers:
Flauer [41]4 years ago
6 0

Answer:

The electric force is 2.2962c + 005 times the gravity force on average human.

Explanation:

Get mass of water in gm

get the mass of protons in 1mL water

get number of electrons that should be present in 1mL of water

electric force Np (protons number), Ne (electrons number)

then get the ratio between the Electric force and weight of average human body;

see workings in attached picture.

Advocard [28]4 years ago
5 0

Answer:

Explanation:

solution answered below

You might be interested in
A projectile is fired with an initial speed of 150 m/s and angle of elevation 60°. (Recall g ≈ 9.8 m/s2. Round your answers to t
natka813 [3]

Answer:

1988 m

Explanation:

Range of a projectile

R = U²sin2∅/g...................... Equation 1

Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.

Given: U = 150 m/s, ∅ = 60°

Constant: g = 9.8 m/s².

Substitute these values into equation 1

R = 150²(sin60°)/9.8

R = 22500(0.866)/9.8

R = 1988 m

Hence the Range of the projectile is 1988 m

4 0
3 years ago
How can wind change landforms
slamgirl [31]
Well, wind can change landforms by storms, and hurricains, or other things that contain air...
~~~~~~~~~~~~~
Like, over a period of time... Wind can make landforms decrease in size, by weathering.
~~~~~~~~~~~~~~
Hope this helps! :)
5 0
3 years ago
Read 2 more answers
The first-order decomposition of cyclopropane has a rate constant of 6.7 × 10–4 s–1. If the initial concentration of cyclopropan
Ket [755]

Answer:

.864 M

Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x  = ? = b( let )

6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315

1.33 / b = e⁰ ⁴³¹⁵ = 1.5395

b = 1.33 / 1.5395 = .864 M.

7 0
4 years ago
Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball tra
Tasya [4]

The formula for kinetic energy is  KE = (1/2) (mass) (speed²)

== The 50 kg ball traveling at 10 m/s has <em>some</em> kinetic energy.  

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = <em>4 times as much</em> kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = <em>1/4 as much</em> kinetic energy.

== A 50 kg <u>person</u> falling at 10 m/s would have <em>exactly the same</em> amount of kinetic energy as the 50 kg <u>ball</u> traveling at 10 m/s.

5 0
3 years ago
Read 2 more answers
Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
lara31 [8.8K]

Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) x=\frac{1}{2}at^2+v_0t+x_0

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) 0=\frac{1}{2}at^2+v_0t

Solving for time t:

-\frac{1}{2}at^2=v_0t

(3) t=-\frac{2v_0}{a}

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) \frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}

Solving equation 4 for acceleration of rocket B:

(5) a_B=a_A\frac{v_{0B}}{v_{0A}}

3 0
3 years ago
Other questions:
  • A speck of dust with mass 12 mg and electric charge 10 μC is released from rest in a uniform electric field of magnitude 850 N/C
    10·1 answer
  • Type of force that keep objects moving in a circle or arv​
    5·1 answer
  • An atomic nucleus is composed of A) protons. B) protons and neutrons. C) protons and electrons. D) protons, neutrons, and electr
    15·2 answers
  • It takes 20 N of force to move a box a distance of 10 m. How much work is done on the box?
    10·1 answer
  • Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
    12·1 answer
  • How is the sun related to nuclear electromagnetic and heat energy?
    10·1 answer
  • How do you get a tachyionic particle and how are they faster than light
    12·1 answer
  • A partly full paint can has 0.67 U.S. gallons of paint left in it. (a) What is the volume of the paint in cubic meters? (b) If a
    11·1 answer
  • 800 has 1 significant digit.
    9·1 answer
  • 7. Answer each of the following questions if the student applied a 550N force to a 100kg box on the same surface. What would be
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!