Answer:
1988 m
Explanation:
Range of a projectile
R = U²sin2∅/g...................... Equation 1
Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.
Given: U = 150 m/s, ∅ = 60°
Constant: g = 9.8 m/s².
Substitute these values into equation 1
R = 150²(sin60°)/9.8
R = 22500(0.866)/9.8
R = 1988 m
Hence the Range of the projectile is 1988 m
Well, wind can change landforms by storms, and hurricains, or other things that contain air...
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Like, over a period of time... Wind can make landforms decrease in size, by weathering.
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Hope this helps! :)
Answer:
.864 M
Explanation:
For first order decomposition,
rate constant k = 1/t x ln a / (a - x )
given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x = ? = b( let )
6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b
ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315
1.33 / b = e⁰ ⁴³¹⁵ = 1.5395
b = 1.33 / 1.5395 = .864 M.
The formula for kinetic energy is KE = (1/2) (mass) (speed²)
== The 50 kg ball traveling at 10 m/s has <em>some</em> kinetic energy.
== A 50 kg ball traveling at 20 m/s would be moving at double the speed. So it would have (2)² = <em>4 times as much</em> kinetic energy.
== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = <em>1/4 as much</em> kinetic energy.
== A 50 kg <u>person</u> falling at 10 m/s would have <em>exactly the same</em> amount of kinetic energy as the 50 kg <u>ball</u> traveling at 10 m/s.
Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1) 
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2) 
Solving for time t:

(3) 
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4) 
Solving equation 4 for acceleration of rocket B:
(5) 