Answer:
Explanation:
velocity of projection, vo = 381 m/s
angle of projection, θ = 73.5°
The formula for the range is
R = 8067.4 m
Range in shorten by 34.1 %
So, the new range is
R' = 8067.4 - 34.1 x 8067.4/100
R' = 5316.4 m
We want to get a better, more concrete idea of the strength of the electric force. So imagine you could remove all the electrons
from 1 mL (1 cubic centimeter) of water. Dump the electrons on yourself, and put the electron-free nuclei (protons and neutrons) on the moon. Estimate how much force will there be between the positive and negative charges? (Of course you have to look up the earth-moon distance.) What fraction of your weight is that force? How many electrons do you have in 1 cc? Consider that virtually all the mass is given by protons and neutrons. Since the proton and the neutron have almost equal masses, and most atoms have equal numbers of protons and neutrons, so the water mass, divided by 2, is the mass of protons. Once you know the total mass of protons, divide by the mass of a single proton and you have the total number of protons. Knowing that, how many electrons do you then suppose you have?)
2 answers:
Answer:
The electric force is 2.2962c + 005 times the gravity force on average human.
Explanation:
Get mass of water in gm
get the mass of protons in 1mL water
get number of electrons that should be present in 1mL of water
electric force Np (protons number), Ne (electrons number)
then get the ratio between the Electric force and weight of average human body;
see workings in attached picture.
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Answer:
The correct answer is
Explanation:
The formula for the electron drift speed is given as follows,
where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.
Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is . Converting this number to m³ using very elementary unit conversion we get
. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,
if we convert the area from mm³ to m³ we get .So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,
which is our final answer.