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jasenka [17]
3 years ago
5

If a ball is given a push so that it has an initial velocity of 5 m/s down a certain inclined plane, then the distance it has ro

lled after t seconds is given by the following equation. s(t) = 5t + 2t2 (a) Find the velocity after 2 seconds.
Physics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

v= 13 m/s

Explanation:

Velocity is defined as the derivative of displacement with respect to time

v= ds/dt

Known data

s(t) = 5t + 2t²  : distance that the ball has rolled after t seconds

vi= 5 m/s : initial velocity

t= 2 s

Problem develoment

s(t) = 5t + 2t²

v= ds/dt= 5 + 4t : velocity of the ball in function of the time

We replace t =2 s in the equation of velocity

v= 5 + 4(2)

v= 13 m/s : velocity after 2 seconds

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182.28 W

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Here ,

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average power supplied = 182.28 W

the average power supplied is  182.28 W

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2. A ball is released from a vertical height of 20 cm. It rolls down a "perfectly
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Answer:

20 cm

Explanation:

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7 0
3 years ago
What is the value of acceleration due to gravity at heght h=4re​
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3 years ago
A projectile is shot on level ground with a
erastova [34]

Answer:

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(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

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3 years ago
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