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jasenka [17]
3 years ago
5

If a ball is given a push so that it has an initial velocity of 5 m/s down a certain inclined plane, then the distance it has ro

lled after t seconds is given by the following equation. s(t) = 5t + 2t2 (a) Find the velocity after 2 seconds.
Physics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

v= 13 m/s

Explanation:

Velocity is defined as the derivative of displacement with respect to time

v= ds/dt

Known data

s(t) = 5t + 2t²  : distance that the ball has rolled after t seconds

vi= 5 m/s : initial velocity

t= 2 s

Problem develoment

s(t) = 5t + 2t²

v= ds/dt= 5 + 4t : velocity of the ball in function of the time

We replace t =2 s in the equation of velocity

v= 5 + 4(2)

v= 13 m/s : velocity after 2 seconds

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You drop an ice cube into an insulated flask full of water and wait for the ice cube to completely melt. The ice cube initially
3241004551 [841]

Answer:T=12.69^{\circ}C

Explanation:

Given

Mass of ice m=60 gm

mass of water M=760 gm

Initial Temperature of water T_i=20^{\circ}C

Let T be the Final Temperature of mixture

Latent heat of Fusion L=334 J/gm

heat required to melt ice completely is

Q_1=60\times 334=20.04 kJ

Heat released by water is taken by ice thus

Mc_{water}(20-T)=mL+mc_{water}(T-0)

0.76\times 4.184\cdot (20-T)=20.04+0.06\times 4.184\cdot (T)

T=12.69^{\circ}C

                       

7 0
3 years ago
Dimension of radius of sphere​
Readme [11.4K]

Answer:

The dimension is L

Explanation:

Dimension analysis is a method of representing quantities majorly with respect to some fundamental quantities of mass (M), length (L), time (T).

A sphere has a definite volume which relates to its radius by:

V = \frac{4}{3}\pir^{3}

In this equation \pi is a dimensionless quantity, and the unit of v is m^{3}.

But, metre is a measure of length, thus it has a dimension of L.

So that,

m^{3} ≅ L^{3}

Then,

L^{3} = r^{3}

Find the cube root of both sides to have,

r = L

Therefore, the dimension of the radius of a sphere is L.

5 0
3 years ago
Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
Ymorist [56]

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

v_2=\frac{34\ g.m/s}{6\ g}\\\\

<u>v₂ = 5.7 m/s</u>

<u></u>

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

4 0
2 years ago
The action of property being taken directly from a person or in that person's presence must be an element in which type of crime
grin007 [14]

B, larceny because that's theft of personal property.

5 0
3 years ago
My Notes Ask Your Teacher 6. Six blocks with different masses, m, each start from rest at the top of smooth, frictionless inclin
Tresset [83]

Answer:

Kf > Ka = Kb > Kc > Kd > Ke

Explanation:

We can apply

E₀ = E₁

where

E₀: Mechanical energy at the beginning of the motion (top of the incline)

E₁: Mechanical energy at the end (bottom of the incline)

then

K₀ + U₀ = K₁ + U₁

If v₀ = 0  ⇒  K₀

and  h₁ = 0   ⇒    U₁ = 0

we get

U₀ = K₁    

U₀ = m*g*h₀ = K₁

we apply the same equation in each case

a) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

b) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

c) U₀ = K₁ = m*g*h₀ = 35 Kg*9.81 m/s²*4m = 1373.40 J

d) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*16m = 1098.72 J

e) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*4m = 274.68 J

f) U₀ = K₁ = m*g*h₀ = 105 Kg*9.81 m/s²*6m = 6180.30 J

finally, we can say that

Kf > Ka = Kb > Kc > Kd > Ke

8 0
3 years ago
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