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frosja888 [35]
2 years ago
9

Please help me with this​

Physics
1 answer:
masha68 [24]2 years ago
7 0

Answer:

>400N is needed to balance that lever

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There are 2.5 cm in a inch if a necklace is 16 inches long how long is it measured in centimeters
wariber [46]
The answer is 840 cm

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3 years ago
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Help please! Test tomorrow!
dlinn [17]

Earth distance to the Sun is about 40 times the Moon's distance from earth.

<u>Explanation:</u>

  • The Earth's distance from the Sun is about 93 million miles. When it expressed in Km, it is 150 million Km.
  • The Moon's distance from Earth is 238,855 miles. When it is 40 times then it will approximately equal to 93 million miles.
  • The Sun's distance from Venus is 67.237 million miles. The Sun's distance from mercury is 35.832 million miles.
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4 years ago
In an electron cloud, an electron farther east away from the nucleus has?
vladimir2022 [97]

An electron that is far away from the nucleus have higher energy than an electron near the nucleus. Nucleus are positively charged and those electrons near it get attracted; those electrons gain kinetic energy hence reducing their internal energy. The electrons far from nucleus have low kinetic energy hence more internal energy.

8 0
3 years ago
Light of a wavelength 610nm is incident on a slit of
aleksandrvk [35]

Answer:

0.00915 m

Explanation:

\lambda = Wavelength of light = 610 nm

L = Distance of slit to screen = 1.5 m

a = Slit gap = 0.2 mm

Width of central maximum is given by

w=\dfrac{2\lambda L}{a}\\\Rightarrow w=\dfrac{2\times 610\times 10^{-9}\times 1.5}{0.2\times 10^{-3}}\\\Rightarrow w=0.00915\ m

The width of the central maximum is 0.00915 m

6 0
4 years ago
Helium-neon laser light (λ = 6.33 × 10−7 m) is sent through a 0.30 mm-wide single slit. What is the width of the central maximum
mixas84 [53]

Answer:

The width is w_c = 0.00422 \ m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  6.33*10^{-7} \ m

    The  width of the slit is  d =  0.3\ mm  =  0.3 *10^{-3} \ m

    The distance of the screen is  D  =  1.0 \ m

     

Generally the central maximum is mathematically represented as

      w_c =  2 *  y

Here  y is the width of the first order maxima which is mathematically represented as

      y =  \frac{\lambda *  D}{d}

substituting values

      y =  \frac{6.33*10^{-7} * 1.0}{ 0.30}

       y =  0.00211 \ m

So  

    w_c =  2 *0.00211

     w_c = 0.00422 \ m

6 0
3 years ago
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