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I am Lyosha [343]
3 years ago
6

Quadrilateral BCDE is inscribed in circle A. The measure of ⏜ is 73°. The measure of ⏜ is 53° and the measure of ⏜ is 102°. Dete

rmine the measure of ∠ BCD.
Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer: c

Step-by-step explanation:

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Solve √(3x+7)+2√(x-8)=0.
laiz [17]

Answer:

The solution to this question is 39

Step-by-step explanation:

Given that :

√(3x+7)+2√(x-8)=0.    

√(3x+7)=-2√(x-8)           (i)

square of the equation (i)

Then

(√(3x+7))^2=(-2√(x-8))^2

we know that √a*√a=(√a)^2=a So,

(3x+7)=4(x-8)      

3x+7=4x-32        //multiply by 4

32+7=4x-3x  exchange the value.

39=1x

x=39.

4 0
3 years ago
Plz help me solve and show your work.
xz_007 [3.2K]

Hi there!

\large\boxed{h = \frac{15x}{y}}

Recall the volume of a pyramid is:

V = 1/3(bh)

We are given the volume and side length of the base. Find the area of the base:

A = s²

A = (5xy²)² = 25x²y⁴

Plug in the solved for base:

125x³y³ = 1/3(25x²y⁴)h

To isolate for h, begin by multiplying both sides by 3:

375x³y³ = (25x²y⁴)h

Divide both sides by 25x²y⁴. Use the following exponent property:

xᵃ / xᵇ = xᵃ⁻ᵇ

Thus:

375x³y³ / 25x²4⁴ = 15x/y.

The height must be equal to:

h = \frac{15x}{y}

7 0
3 years ago
You are going to order some T-shirts and sun hats online for all
Lera25 [3.4K]

Answer:

20

Step-by-step explanation:

you need to subtract the 10 from 1,370

then youcan add 55 and 13 you get 68

then you dived 1,370 by 68

you get 20.14705882 you round and get 20

3 0
3 years ago
Read 2 more answers
Un dirigible que está volando a 800 m de altura, distingue un pueblo con un ángulo de depresión de 12°. ¿A qué distancia del pue
alexira [117]

Answer:

3764 m

Step-by-step explanation:

Resolvemos usando la función trigonométrica de tangente.

tan θ = Opuesto / Adyacente

θ = Ángulo de depresión = 12 °

Opuesto = 800m

Adyacente = Distancia de la ciudad = x

Cruz multiplicar

bronceado 12 = 800 / x

Cruz multiplicar

bronceado 12 × x = 800

x = 800 / tan 12

x = 3763.7040876 m

Aproximadamente = 3764 m

6 0
3 years ago
There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. The total
scZoUnD [109]

The total numbers of sections are 16.

Step-by-step explanation:

Given:

Number of boys in school = 576

Number of girls in school = 448

To find: Total Number of sections such that each section has either boys or girls.

Height Common Factor ( HCF ) of both number gives the number of students in a section.

HCF of 576 and 448

576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

448 = 2 × 2 × 2 × 2 × 2 × 2 × 7

HCF = 2 × 2 × 2 × 2 × 2 × 2 = 64

Number of sections of Boys = 576/64 = 9

Number of sections of girls 448/64 = 7

Total Number of sections = 9 + 7 = 16

Therefore, The total numbers of sections are 16.

6 0
3 years ago
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