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3 years ago

5

You see a flash of lightning and hear thunder 3 seconds later. If the air temperature is 24°C that day, determine how far away t

he storm is.

1 answer:

avanturin [10]3 years ago

4 0

Answer:

Explanation:

speed of sound in 24 degrees celsius

345.48m/s

hence 345.48m/s x 3s = 1036.44m

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Jayda wants to study the chemical properties of iron. How could she do this?

Bess [88]

yes she could she can do one peace of her iron and she can do the rest of it tomorrow

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4 years ago

It has been suggested that rotating cylinders about 14.5 mi long and 4.78 mi in diameter be placed in space and used as colonies

taurus [48]

Angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.0466 rad/s.

Length of the cylinder, L = 9 mi

= (14.5mi)(1609.344 m / 1 mi)

= 23,335.48 m

Diameter of the cylinder, D = 4.78 mi

= (4.78 mi)(1609.344 m / 1 mi)

= 7692.645 m

Radius of the cylinder, r = D / 2

= ( 7692.645 m) / 2

= 3846.32 m

Centripetal acceleration is given by, ac = v^2 / r

We have the relation between linear velocity (v) and the angular velocity(ω) as

v = r ω

Then, ac = v2 / r

= (rω)2 / r

ac = ω^2 r

If the centripetal acceleration is equals the free fall acceleration of earth, then

ω^2 r = g

ω=0.0466 rad/s

Angular acceleration is the term used to describe the rate of change in angular velocity. If the angular velocity is constant, the angular acceleration is constant.

To know more about angular velocity visit : brainly.com/question/12446100

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7 0

1 year ago

What distance will a vehicle travel before coming to a complete stop from a speed of 70 mph, (a) When the vehicle is traveling o

OLga [1]

Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

We need to calculate the stopping sight distance

Using formula of SSD

$SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}$

Where, v = speed of vehicle

t = perception reaction time

f = coefficient of friction

g = gradient of road

(a). If the gradient of road is zero.

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}$

$SSD=723.9\ ft$

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}$

$SSD=620.2\ ft$

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be $723.91>SSD>620.2$

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}$

$SSD=910.5\ ft$

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

7 0

3 years ago

There is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.

igor_vitrenko [27]

Mass=2kg
Velocity=40m/s

We know

$\boxed{\sf K.E=\dfrac{1}{2}mv^2}$

m denotes to mass
v denotes to velocity

$\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2$

$\\ \sf\longmapsto K.E=40^2$

$\\ \sf\longmapsto K.E=1600J$

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3 years ago

What is the group name in which helium is found?

lesya692 [45]

Is is found in the noble gases group

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4 years ago