All categories

3 years ago

Will give brainliest

Physics

2 answers:

julsineya [31]3 years ago

6 0

Group 18 is the answer

Nostrana [21]3 years ago

5 0

Answer:

I think 18 not entirely sure though

Explanation:

Group 18 are the noble group so 16 + 2 = 18

You might be interested in

A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radi

andreev551 [17]

Answer:2

Explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim $r=20 cm$

mass of rim $m=2 kg$

Angular momentum $\vec{L}=I\cdot \vec{\omega }$

$I=mr^2=2\times 0.2^2=0.08 kg-m^2$

$\omega =\frac{v}{r}=\frac{5}{0.2}=25 rad/s$

$L=0.08\times 25=2kg-m^2/s$

direction of Angular momentum will be towards west

7 0

3 years ago

In how many places did the object stop moving? How do you know?

scZoUnD [109]

Explanation:

The object stops moving in 5 places (namely B, D, F, H, and position after 28 seconds which isn't marked ).

We know that the object has stopped moving, since its position does not change with the passage of time i.e. at rest.

6 0

3 years ago

Pure water has a pH of 7. Pure water _______. A. is a neutral substance B. could be either an acid or a base C. is a base D. is

malfutka [58]

A. is a neutral substance.

Only neutral substances (like pure water) can have a pH of 7.

5 0

3 years ago

Read 2 more answers

An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit

lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is $1.127\times 10^7m/s$

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

$m_1v_1=m_2v_2$

where,

$m_1\text{ and }v_1$ = Initial mass and velocity

$m_2\text{ and }v_2$ = Final mass and velocity

We are given:

$m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s$

Putting values in above equation, we get:

$238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s$

Hence, the velocity of released alpha particle is $1.127\times 10^7m/s$

4 0

3 years ago

Light enters an equilateral prism with an incident angle of 35Â° to the normal of the surface. Calculate the angle at which the

julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

$n=\frac{Sini}{Sinr}$

$1.5=\frac{Sin35}{Sinr}$

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

$\frac{1}{n}=\frac{Sinr'}{Sini'}$

Where, i' be the angle at which the light exit from other surface.

$\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}$

Sin i' = 0.913

i' = 65.9°

4 0

3 years ago