Question

Light enters an equilateral prism with an incident angle of 35° to the normal of the surface. Calculate the angle at which the light exits on the opposite side. The index of refraction of the glass is 1.50.

Answer 1

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

$n=\frac{Sini}{Sinr}$

$1.5=\frac{Sin35}{Sinr}$

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

$\frac{1}{n}=\frac{Sinr'}{Sini'}$

Where, i' be the angle at which the light exit from other surface.

$\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}$

Sin i' = 0.913

i' = 65.9°