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Finger [1]
1 year ago
13

34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. He

r car has a mass of
34.01 kg (75 lbs). The race lasts just 30 seconds. You think if her car attains an acceleration of 0.55 m/s² to attain a final velocity of 16.54 m/s
(37mph), she will win the race. What force would be needed to accomplish this goal.
Physics
1 answer:
Elden [556K]1 year ago
4 0

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

Newton's Second Law of Motion states that acceleration (a) happens when a force (F) acts on a mass (m).

We want a car of mass 34.01 kg to have an acceleration of 0.55 m/s². We can calculate the required force using Newton's Second Law of Motion.

F = m × a = 34.01 kg × 0.55 m/s² = 19 N

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion here: brainly.com/question/25545050

#SPJ1

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Weight is used most often for measuring____________________ whereas volume is used most often for measuring_____________________
Alex777 [14]

Answer:

Weight is used most often for measuring solid whereas volume is used most often for measuring liquid.

Explanation:

Weight is used most often for measuring solid, because solids have definite shape.  Weight is usually expressed in Newton (N) because it is a function of mass and gravity. ( weight = mass x gravity).

Whereas  volume is used most often for measuring liquid, usually expressed in cubic meter (m³) because liquids have no definite shape, rather they occupy the volume of their container.

6 0
2 years ago
During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

a=\frac{v^2}{r}

r is the radius of the loop

on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

or

r = 1472.98 m

5 0
3 years ago
Convert the mass to kgs thanks
Natali [406]
Memorize this and you'll be able to do ALL of these:  <em>1  kg = 1,000 g</em>

So if you have some grams, divide the number by 1,000 to get kilograms.

1,000 g = 1.000 kg

500 g = 0.500 kg

100 g = 0.100 kg

50 g = 0.050 kg

20 g = 0.020 kg

10 g = 0.010 kg
4 0
2 years ago
A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a
Fudgin [204]

Answer:

Temperature will be 305 K  

Explanation:

We have given The asteroid has a surface area A=7.70m^2

Power absorbed P = 3800 watt

Boltzmann constant \sigma =5.67\times 10^{-8}Wm/K^4

According to Boltzmann rule power radiated is given by

P=\sigma AT^4

3800=5.67\times 10^{-8}\times 7.70\times T^4

T^4=87.0381\times 10^8

T=305K

So temperature will be 305 K  

8 0
3 years ago
Assume that a vaulter is able to carry a vaulting pole while running as fast
rewona [7]
A,walls
Speleleelelelekeke
8 0
3 years ago
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