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Finger [1]
2 years ago
13

34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. He

r car has a mass of
34.01 kg (75 lbs). The race lasts just 30 seconds. You think if her car attains an acceleration of 0.55 m/s² to attain a final velocity of 16.54 m/s
(37mph), she will win the race. What force would be needed to accomplish this goal.
Physics
1 answer:
Elden [556K]2 years ago
4 0

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

Newton's Second Law of Motion states that acceleration (a) happens when a force (F) acts on a mass (m).

We want a car of mass 34.01 kg to have an acceleration of 0.55 m/s². We can calculate the required force using Newton's Second Law of Motion.

F = m × a = 34.01 kg × 0.55 m/s² = 19 N

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion here: brainly.com/question/25545050

#SPJ1

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no

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Figure one, voltmeters
slava [35]

Answer:

(i) Half

(ii) 3 V

(iii) V₁

Explanation:

(i) The given parameters are;

The circuits have identical resistances

The number of resistors in circuit 1 = 1 resistor

The number of resistors in circuit 2 = 2 resistors

Let 'R' represent the value of each resistor, we have;

The total resistance of circuit 1 = R Ohm

The total resistance of circuit 3 = 2·R Ohm

∴ The total resistance of circuit 1  = (1/2) × The total resistance of circuit 3

∴ The resistance of circuit 1 is <u>half</u> the resistance of circuit 3

(ii) The potential difference of each cell, V = 1.5 volts

The number of cells in circuit 2 = 2 cells

The total potential difference of the cells of circuit 2 = 2 × 1.5 volts = 3 × volts = 3 V.

The voltmeter reading = The potential difference across the cell or cells it is applied

∴ The voltmeter reading on voltmeter, V₂, applied across the cells of circuit 2 = 3 V

(iii) The voltmeter reading V₁ = 1.5 V

The voltmeter reading V₂ = 3 V

The voltmeter reading V₃ = 4.5/(2·R) × R = 2.25 V

Therefore, the voltmeter reading with the smallest volt, is V₁ = 1.5 V

6 0
3 years ago
A hiker walks due east for a distance of 25.5 km from her base camp. On the second day, she walks 41.0 km northwest till she dis
GarryVolchara [31]

Resultant displacement is 29.2 km at 83.1^{\circ} north of west

Explanation:

To solve the problem, we have to use the rules of vector addition, resolving first each vector along the x- and y- direction.

Taking east as positive x direction and north as positive y- direction, we have:

- First displacement is 25.5 km east, therefore its components are

A_x = 25.5 km\\A_y = 0 km

- Second displacement is 41.0 km northwest, so its components are

B_x = (41.0)cos(135^{\circ})=-29.0 km\\B_y =(41.0)sin(135^{\circ})=29.0 km

So, the components of the resultant displacement are

R_x=A_x+B_x=25.5+(-29.0)=-3.5 km\\R_y=A_y+B_y=0+29.0=29.0 km

And so, the magnitude is calculated using Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}=\sqrt{(-3.5)^2+(29.0)^2}=29.2 km

And the direction is given by

\theta=tan^{-1}(\frac{R_y}{|R_x|})=tan^{-1}(\frac{29.0}{3.5})=83.1^{\circ}

Where the angle is measured from the west direction, since Rx is negative.

Learn more about displacement:

brainly.com/question/3969582

#LearnwithBrainly

3 0
3 years ago
A janitor standing on the top floor of a building wishes to determine the depth of the elevator shaft. They drop a rock from res
Bumek [7]

Answer:

Part a)

H = 26.8 m

Part b)

error = 7.18 %

Explanation:

Part a)

As the stone is dropped from height H then time taken by it to hit the floor is given as

t_1 = \sqrt{\frac{2H}{g}}

now the sound will come back to the observer in the time

t_2 = \frac{H}{v}

so we will have

t_1 + t_2 = 2.42

\sqrt{\frac{2H}{g}} + \frac{H}{v} = 2.42

so we have

\sqrt{\frac{2H}{9.81}} + \frac{H}{336} = 2.42

solve above equation for H

H = 26.8 m

Part b)

If sound reflection part is ignored then in that case

H = \frac{1}{2}gt^2

H = \frac{1}{2}(9.81)(2.42^2)

H = 28.7 m

so here percentage error in height calculation is given as

percentage = \frac{28.7 - 26.8}{26.8} \times 100

percentage = 7.18

5 0
3 years ago
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