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Finger [1]
2 years ago
13

34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. He

r car has a mass of
34.01 kg (75 lbs). The race lasts just 30 seconds. You think if her car attains an acceleration of 0.55 m/s² to attain a final velocity of 16.54 m/s
(37mph), she will win the race. What force would be needed to accomplish this goal.
Physics
1 answer:
Elden [556K]2 years ago
4 0

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

Newton's Second Law of Motion states that acceleration (a) happens when a force (F) acts on a mass (m).

We want a car of mass 34.01 kg to have an acceleration of 0.55 m/s². We can calculate the required force using Newton's Second Law of Motion.

F = m × a = 34.01 kg × 0.55 m/s² = 19 N

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion here: brainly.com/question/25545050

#SPJ1

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IrinaK [193]

Answer:

  • <u>verbal,</u>
  • <u> Intrapersonal</u>

Explanation:

Remember, we are told that "Professor Wooddro<em> </em><em>teaches an Introduction to Philosophy at the college, and loves to talk about the meaning of life and death"</em> which would require having verbal intelligence (the ability to understand and relate information using words).

Intrapersonal intelligence is also reflected by Professor Wooddro as we are told he "enjoys struggling with life's most challenging questions", <u>which shows his knowledge of his own strengths or weaknesses.</u>

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3 years ago
When the Moon orbits Earth, what is the centripetal force?
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Answer:

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Explanation:

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3 years ago
a concrete cube of side 0.50 m and uniform density 2.0 x 103 kg m–3 is lifted 3.0 m vertically by a crane. what is the change in
AlladinOne [14]

Answer:

Change in potential energy = 7350 Joules

Explanation:

It is given that,

Side of cube, a = 0.5 m

Density of cube, d=2\times 10^3\ kg/m^3

The cube is lifted vertically by a crane to a height of 3 m

We know that, density d=\dfrac{m}{V}

So, m = d × V  (V = volume of cube = a³)

m=2\times 10^3\ kg/m^3\times (0.5\ m)^3

m = 250 kg

We have to find the change in potential energy of the cube. At ground level, the potential energy is equal to 0.

Potential energy at height h is given by :

PE=mgh

PE = 250 kg × 9.8 m/s² ×3 m

PE = 7350 Joules

So, change in potential energy of the cube is 7350 Joules.

5 0
3 years ago
Read 2 more answers
What is the speed of a car that travels 48 km in 2 hours?
ankoles [38]
Speed=distance/time

distance =48km
time=2 hours

speed=48/2
=24km/h


speed=24km/h

FORMULAS

speed = distance/time
time = distance/speed
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3 0
3 years ago
Dante is leading a parade across the main street in front of city hall. Starting at city hall, he marches the parade 4 blocks ea
Ipatiy [6.2K]

Answer:

The correct option is A)

Displacement: 6.71 m, Direction: 63.4 degrees north of east

Explanation:

Given that Dante is leading a parade across the main street in front of city hall.

Let, Initial location of parade is 0i+0j

One block of city is one units on the XY- graph

Statement 1: Parade marches the parade 4 blocks east, then 3 blocks south

New location of parade is 4i-3j

Statement 2: The parade marches 1 block west and 9 blocks north and finally stops.

Final location of parade is (4i-3j)+(-1i+9j)=3i+6j

Displacement is given by

Displacement = (Final destination)-(Initial destination)

Displacement = (3i+6j)-(0i+0j)=3i+6j

Thus,

Magnitude of displacement = \sqrt{3^{2}+6^{2}}

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Direction of displacement =  tan^{-1}(\frac{Y}{X} )

                                           =  tan^{-1}(\frac{6}{3} )

                                           = 63.43 NE

Therefore, the correct option is A) Displacement: 6.71 m, Direction: 63.4 degrees north of east

5 0
3 years ago
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