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Anarel [89]
3 years ago
6

If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons?

Physics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

Mass = 130 lbs

But, 2.2 lbs = 1.0 kg

130 lbs to kg = 130 * 2.2 = 286 kg

Acceleration due to gravity = 9.8m/s²

To find the force in Newton;

Force = mass * acceleration due to gravity

Force = 286 * 9.8

Force = 2802.8 Newton

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irina1246 [14]

Answer: 2400m

Explanation: 2400m because 600 times 4 equals 2400

6 0
3 years ago
In the sum →A+→B=→C, vector →A has a magnitude of 12.0 m and is angled 40.0° counterclockwise from the +x direction, and vector
icang [17]

Answer:

Explanation: Ok, first caracterize the two vectors that we know.

A = ax + ay = (12*cos(40°)*i + 12*sin(40°)*j) m

now, see that C is angled 20° from -x, -x is angled 180° counterclockwise from +x, so C is angled 200° counterclockwise from +x

C = cx + cy = (15*cos(200°)*i + 15*sin(200°)*j) m

where i and j refers to the versors associated to te x axis and the y axis respectively.

in a sum of vectors, we must decompose in components, so: ax + bx  = cx and ay + by = cy. From this two equations we can obtain B.

bx= (15*cos(200°) - 12*cos(40°)) m = -23.288 m

by = (15*sin(200°) - 12*sin(40°)) m = -12.843 m

Now with te value of both components of B, we proceed to see his magnitude an angle relative to +x.

Lets call a to the angle between -x and B, from trigonometry we know that tg(a) = by/bx, that means a = arctg(12.843/23.288) = 28.8°

So the total angle will be 180° + 28.8° = 208.8°.

For the magnitude of B, lets call it B', we can use the angle that we just obtained.

bx = B'*cos(208.8°) so B' = (-23.288 m)/cos(208.8°) =  26.58 m.

So the magnitude of B is 26.58 m.

7 0
3 years ago
Energy created by the flow of electrons through a conductor.
kodGreya [7K]
The first one is electrical energy
3 0
3 years ago
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Alinara [238K]

Answer:

The last one is false

Explanation:

Energy can be neither created or destroyed. It can only move from one type of energy to another.

6 0
3 years ago
Constants Part A wo charged dust particles exert a force of 7.5x102 N n each other What will be the force if they are moved so t
alexandr1967 [171]

Answer:

New force, F'=48\times 10^3\ N

Explanation:

It is given that,

Force acting between two charged particles, F=7.5\times 10^2\ N

We need to find the force if they are moved so they are only one-eighth as far apart.

The force between two charged particles separated at a distance of r is given by :

F=k\dfrac{q_1q_2}{r^2}............(1)

If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :

F'=k\dfrac{q_1q_2}{(\dfrac{r}{8})^2}..........(2)

Dividing equation (1) and (2) :

\dfrac{F}{F'}=\dfrac{1}{64}

F'=7.5\times 10^2\ N\times 64

F' = 48000 N

or

F'=48\times 10^3\ N

Hence, this is the required solution.

8 0
3 years ago
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