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bulgar [2K]
3 years ago
13

Talia is on a trip with some friends. In the first 2 hours , they travel 100 miles. Then they hit traffic and go only 30 miles i

n the next hour. The last hour of their trip , they drive 75 miles
Physics
1 answer:
jeka943 years ago
5 0

Answer:

51 miles/hour

Explanation:

<em>Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.</em>

<em />

<em>The average speed would be 51 miles/hour.</em>

<u>The average speed of a moving object is defined as the total distance traveled relative to the total time taken fro the journey. Mathematically, it is given as:</u>

  total distance traveled/total time taken.

In this case;

Total distance traveled = 100 + 30 + 75 = 205 miles

Total time taken = 2 + 1 + 1 = 4 hours

Therefore;

Average speed = 205/4 = 51.25 miles/hour

<em>To the nearest whole number = 51 miles/hour</em>

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Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

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We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

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3 years ago
A nonrelativistic electron is accelerated from rest through a potential difference. After acceleration the electron has a de Bro
aleksley [76]

Answer:

Potential difference though which the electron was accelerated is 2.67\times 10^{-6}\ uV\  .

Explanation:

Given :

De Broglie wavelength , \lambda=750\ nm.

Plank's constant , h=6.626\times 10^{-34}\ J.s \ .

Charge of electron , e=-1.6\times 10^{-19}\ C.

Mass of electron , m=9.11\times 10^{-31}\ kg.m=9.11\times 10^{-31}\ kg.

We know , according to de broglie equation :

\lambda=\dfrac{h}{mv}\\\\ v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.626\times 10^{-34}\ J.s \ }{9.11\times 10^{-31}\ kg\times 750\times 10^{-9}\ m }= 969.78\ m/s .

Now , we know potential energy applied on electron will be equal to its kinetic energy .

Therefore ,

qV=\dfrac{mv^2}{2}\\\\ V=\dfrac{mv^2}{2q}

Putting all values in above equation we get ,

V=2.67\times 10^{-6}\ uV .

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3 years ago
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4vir4ik [10]

Answer:

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Explanation:

6 0
2 years ago
5. An ion consist of 12 electrons and 11 proton. What is the charge<br> on the ion?
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Answer:

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U = 1.134 J

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3 years ago
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