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sattari [20]
3 years ago
6

How can citizens affect environmental policy at the local, state, and national levels

Physics
1 answer:
Bingel [31]3 years ago
3 0
You can send in a letter or request to change or enforce a policy. You can also protest or elect officials that agree with you.<span />
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Define fractional distillation
Serga [27]

Answer:

separation of a liquid mixture into fractions differing in boiling point (and hence chemical composition) by means of distillation, typically using a fractionating column.

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3 years ago
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If you wanted to estimate how much money a certain appliance costs you, how would you do it?
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Interesting question.

There are a number of factors that may attribute to the pricing of an item say quality of material, number of special features available, and certainly a common notion of brand value (e.g H&M vs GUCCI). Of course, it does not necessarily mean more face value = more expensive.

Typically, to estimate, I would check the brand and material component.

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4 years ago
In beta decay, what is emitted?
FrozenT [24]
An electron is emitted in both positive and negative beta decay, although the positive one is called positron emission.
8 0
3 years ago
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Two or more velocities add by ____?<br><br> Plz help
VladimirAG [237]
By vector addition.
In fact, velocity is a vector, with a magnitude intensity, a direction and a verse, so we can't simply do an algebraic sum of the two (or more velocities). 
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R= \sqrt{(R_x)^2+(R_y)^2}
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3 0
3 years ago
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A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an
olya-2409 [2.1K]

Answer:

289282

Explanation:

r = Radius of plate = 0.52 mm

d = Plate separation = 0.013 mm

A = Area = \pi r^2

V = Potential applied = 2 mV

k = Dielectric constant = 40

\epsilon_0 = Electric constant = 8.854\times 10^{-12}\ \text{F/m}

Capacitance is given by

C=\dfrac{k\epsilon_0A}{d}

Charge is given by

Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}

Number of electron is given by

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}

The number of charge carriers that will accumulate on this capacitor is approximately 289282.

6 0
3 years ago
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