A small charge q is placed near a large spherical charge Q. The force experienced by both charges is F. The electric eld created
1 answer:
The electric field created by Q at the position of q is .
The given parameters:
- <em>Magnitude of charge, = q</em>
- <em>Spherical charge, = Q</em>
- <em>Force experienced by both charges, = F</em>
The electric field created by Q at the position of q is calculated as follows;
where;
- <em>E is the magnitude of electric field strength </em>
- <em>F is the force experienced by both charges</em>
- <em>Q is the charge</em>
Thus, the electric field created by Q at the position of q is .
Learn more about electric field here: brainly.com/question/14372078
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Answer:
Answer D : about 1067 meters
Explanation:
There are two steps to this problem:
1) First find the time it takes the plane to stop using the equation for the acceleration:
Where Vf is the final velocity of the plane (in our case: zero )
Vi is the initial velocity of the plane (in our case: 80 m/s)
is the acceleration (in our case -3 m/s^2 - notice negative value because the velocity is decreasing)
with units corresponding to seconds given the quantities involved in the calculation.
2) Second knowing the time it took the plane to stop, now use that time in the equation for the distance traveled under accelerated motion:
Where the answer results in units of meters given the quantities used in the calculation.
We round this to 1067 meters
Answer:
8 signals received by twin A during the trip.
Explanation:
Given that,
Distance = 12 light year
Speed = 0.6 c
Time = 1 year
We need to calculate the time by A
Using formula of time
Put the value into the formula
Similarly,
The expression for distance cover by A
We need to calculate the time
Using formula of time
We need to calculate the signals received by twin A
Using formula for number of signals
Put the value into the formula
Hence, 8 signals received by twin A during the trip.
this process is called parellelogram method of resolving vectors.
