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3 years ago

Which of the following is an accurate statement?

Physics

1 answer:

cestrela7 [59]3 years ago

4 0

A OR D ARE THE TWO ANSWERS I THINK

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What is measurement

Sliva [168]

Answer:

There is no measurment

Explanation:

Have an amazing day!

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3 years ago

When energy decreases, particle motion:<br> A. stops<br> B. increases<br> C. decreases

DaniilM [7]

C. decreases here you go

7 0

3 years ago

Read 2 more answers

A 5000kg car traveling at 40m/s crashes into a wall and comes to a complete stop in 10ms. What was the force on the wall?

Kisachek [45]

Answer:

20,000,000 N

Explanation:

First find the acceleration:

a = Δv / Δt

a = (0 − 40 m/s) / 0.010 s

a = -4000 m/s²

Next use Newton's second law to find the force on the car:

F = ma

F = (5000 kg) (-4000 m/s²)

F = -20,000,000 N

According to Newton's third law, the force on the wall is equal and opposite the force on the car.

F = 20,000,000 N

7 0

3 years ago

How do you think the formation of new stars is related to supernovas and planetary nebulae?

kogti [31]

By God wanting them to be the same kinda

5 0

4 years ago

The 160-lblb crate is supported by cables ABAB, ACAC, and ADAD. Determine the tension in these wire

kakasveta [241]

Answer:

$F_{AB} = 172.1356\\F_{AC} = 258.2033\\F_{AD} = 368.8004$

Explanation:

Using the diagram (see attachment) we extract the following position vectors:

$Vector (OA) = 6i + 0j + 0k \\Vector (OB) = 0i + 3j + 2k \\Vector (OC) = 0i - 2j + 3k$

Next step is to find unit vectors $u_{AB} ,u_{AC}, u_{AD}, u_{AE}$ as follows:

$u_{AB} = \frac{vector(AB)}{magnitude(AB)} \\= \frac{OB - OA}{magnitude({vector(OB - OA))} }\\=\frac{-6i +3j+2k}{\sqrt{6^2 + 3^2+2^2} } \\\\=-0.857 i +0.429j+0.286k\\\\u_{AC} = \frac{vector(AC)}{magnitude(AC)} \\= \frac{OC - OA}{magnitude({vector(OC - OA))} }\\=\frac{-6i -2j-3k}{\sqrt{6^2 + 2^2+3^2} } \\\\=-0.857 i -0.286j+0.429k\\\\u_{AD} = +1i\\u_{AC} = -1k$

Using the diagram we find the corresponding vectors Forces:

$F_{AB} = F_{AB} i + F_{AB}j +F_{AB}k\\F_{AC} = F_{AC} i + F_{AC}j +F_{AC}k\\F_{AD} = F_{AD} i + F_{AD}j +F_{AD}k\\W = -160 k$

Equation of Equilibrium:

$Sum of forces = 0\\F_{AB}. u_{AB} + F_{AC}.u_{AC} + F_{AD}.u_{AD} + W = 0\\(-0.857F_{AB}i + 0.429F_{AB}j +0.286F_{AB}k) + (-0.857F_{AC}i - 0.286F_{AC}j +0.429F_{AC}k) + (+1F_{AD} i) + (-160k) = 0$

Comparing i , j and k components as follows:

$-0.857F_{AB} -0.857F_{AC} +1F_{AD} = 0\\+ 0.429F_{AB} - 0.286F_{AC} = 0\\+0.286F_{AB} +0.429F_{AC} = 160$

Solving Above equation simultaneously we get:

$F_{AB} = 172.1356\\F_{AC} = 258.2033\\F_{AD} = 368.8004$

3 0

4 years ago