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3 years ago

Can someone answer this please I’ll give brainliest

Physics

1 answer:

Alinara [238K]3 years ago

6 0

Answer:

The last one is false

Explanation:

Energy can be neither created or destroyed. It can only move from one type of energy to another.

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9. Batman (mass=91 kg) jumps straight down from a bridge into a boat (mass=510 kg) in which a criminal is fleeing. The velocity

Ierofanga [76]

Answer:

V = 9.33 m/s

Explanation:

Given that,

Mass of the batsman, $m_1=91\ kg$

Mass of the boat, $m_2=510\ kg$

Initial speed of the boat, v = 11 m/s

Let V is the velocity of the boat after Batman lands in it. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

$510\times 11=(91+510)V$

$V=\dfrac{510\times11}{(91+510)}$

V = 9.33 m/s

So, the velocity of the boat after Batman lands in it 9.33 m/s. Hence, this is the required solution.

5 0

3 years ago

When all individual forces acting upon an object are balanced, it is the natural tendency of the object to

sleet_krkn [62]

Answer:

- maintain its state of motion

- Keep its velocity constant (either at zero or non-zero value)

8 0

3 years ago

Paul is given assistance with finding a job and an apartment, and learning to correctly take his medications. Paul is most likel

o-na [289]

The answer is B. Insight therapy

6 0

4 years ago

Steam enters an adiabatic turbine at 6 MPa, 600 ℃, and 80 m/s and leaves at 50 kPa, 100 ℃, and 140 m/s. If the power output of t

lisabon 2012 [21]

Answer:

W(r,out) = 5.81 MW

$\eta$ = 86.1 %

Explanation:

we use here steam table for get value of h1, s1 etc

so use for 6MPa and 600 degree

Enthalphy of steam h1 = 3658.8 kJ/kg

Entropy of steam s 1 is = 7.1693 kJ /kg.K

and

for 50 kPa and 100 degree

Enthalphy of steam h2 = 2682.4 kJ/kg

Entropy of steam s2 is = 7.6953 kJ /kg.K

so we use here energy balance equation that is

$m\times(h1 + \frac{v1^2}{2} = m\times(h2 + \frac{v2^2}{2} + W(out)$ ..............1

put here value and we get m

m = $\frac{5\times1000}{3658.8-2682.4+\frac{80^2-140^2}{2}\times \frac{1}{1000}}$

solve it we get

m = 5.156 kg/s

so by energy balance equation

m $\psi$ 1 = m $\psi$ 2 + W(r,out)

W(r,out) = m( $\psi$ 1 - $\psi$ 2)

W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)

W(r,out) = $m[h1-h2+ \frac{v1^2-v^2}{2}- To (s1-s2)$

W(r,out) = W(a,out) - m.To.(s1-s2) ........................2

put here value

W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)

W(r,out) = 5908.19 = 5.81 MW

and

second law deficiency is

$\eta$ = $\frac{W(a,out)}{W(r,out)}$ ..............................3

put here value

$\eta$ = \frac{5}{5.81}

$\eta$ = 86.1 %

6 0

3 years ago

Define reference point <br><br><br>plz help me

xeze [42]

Answer:

a basis or standard for evaluation, assessment, or comparison; a criterion.

Explanation:

Definition of reference point. : something that is used to judge or understand something else The professor used the study as a reference point for evaluating and discussing other theories.

8 0

3 years ago

Read 2 more answers