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2 years ago

A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?

Physics

2 answers:

lesantik [10]2 years ago

6 0

Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3

densk [106]2 years ago

6 0

Answer:

Volume, $V=4.82\ cm^3$

Explanation:

Given that,

Mass of the lead ball, m = 55 grams

Density of lead ball, $d=11.4\ g/cm^3$

We need to find the volume of the ball. The formula of density is given by :

$d=\dfrac{m}{V}$

$V=\dfrac{m}{d}$

$V=\dfrac{55\ g}{11.4\ g/cm^3}$

$V=4.82\ cm^3$

So, the volume of the the lead ball is

$V=4.82\ cm^3$ . Hence, this is the required solution.

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2 years ago

A heavy stone of mass m is hung from the ceiling by a thin 8.25-g wire that is 65.0 cm long. When you gently pluck the upper end

Triss [41]

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Explanation:

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v= $\sqrt{\frac{Tension}{Linear. Mass. density} }$

Here, Tension= m*g = m*9.81

and linear mass density= $\frac{8.25 g}{65 cm}$

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v= $\sqrt{\frac{Tension}{Linear. Mass. density} }$

165.8= $\sqrt{\frac{m*9.81}{0.0127} }$

Solving we get

m= 35.58 kg

or m= 35.6 kg

3 0

3 years ago

Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc

Paraphin [41]

Answer:

$V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}$

Explanation:

The 4 wires are connected in series: this means that the same current flow through them, and the voltage of the battery, V0, is equal to the sum of the voltages on each individual resistor:

$V_0=V_1+V_2+V_3+V_4$

Also, the equivalent resistance of the series circuit is

$R_{eq}=R_1+R_2+R_3+R_4$

The voltage V2 across wire 2 is given by Ohm's law:

$V_2 = R_2 I$ (1)

where I is the total current in the circuit, which is given by:

$I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}$

Substituting this into eq. (1), we find an expression for V2:

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8 0

2 years ago

What’s the voltage of a battery in a circuit with resistance of 3 ohms and current of 5 amps?

alexira [117]

Answer: The correct answer is-15 Volts.

Explanation-

Voltage of a battery can be defined as the difference in electric potential that lies between the positive and negative terminals of a battery.

It can be calculated using Ohm's law, which states that the electric potential difference between two points on a circuit is equal to the product of the current that flows between the two points (I) and the total resistance that sis present between the two points. It can be mathematically depicted as-

ΔV = I • R

Putting the value of 'I' and 'R', we get-

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8 0

2 years ago

water flows horizontally from a hose that is 3m above the ground. the water lands 7.2m to the right of the hose . how long does

Sidana [21]

Answer:

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t = 0.782 s

Round as needed.

8 0

2 years ago

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