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natta225 [31]
2 years ago
15

A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?

Physics
2 answers:
lesantik [10]2 years ago
6 0
Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3
densk [106]2 years ago
6 0

Answer:

Volume,V=4.82\ cm^3

Explanation:

Given that,

Mass of the lead ball, m = 55 grams

Density of lead ball, d=11.4\ g/cm^3

We need to find the volume of the ball. The formula of density is given by :

d=\dfrac{m}{V}

V=\dfrac{m}{d}

V=\dfrac{55\ g}{11.4\ g/cm^3}

V=4.82\ cm^3

So, the volume of the the lead ball is

V=4.82\ cm^3. Hence, this is the required solution.

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A tank contains 350 liters of fluid in which 10 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
aleksandr82 [10.1K]

Answer:

A(t) = -340e^{-t/70} + 350

Explanation:

Since fluid is pumping in and out at the same rate (5L/min), the total fluid volume in the tank stays constant at 350L. Only the amount of salt and its concentration changed overtime.

Let A(t) be the amount of salt (g) at time t and C(t) (g/L) be the concentration at time t

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Brine with concentration of 1g/L is pouring in at the rate of 5L/min so the salt income rate is 5 g/min

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This is a first-order linear ordinary differential equation and it has the form of y' = a + by. The solution of this is

y = ce^{bt} + \frac{a}{b}

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4 0
3 years ago
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