Answer:
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Step-by-step explanation:
Let's solve for x.
3x2+y2=9
Step 1: Add -y^2 to both sides.
3x2+y2+−y2=9+−y2
3x2=−y2+9
Step 2: Divide both sides by 3.
3x^2/3= -y^2+9/3
x^2=-1/3 y^2 +3
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Hope it helped!
Sum of square of two sides must be equal to the square of third side.
So what you do is distribute the invisible -1 in front of the second parenthasees set and add like terms
remember
x^2+3x^2=4x^2
-(3+4x-x^2)=-1(3x+4x-x^2)=-3-4x+x^2
so first distribute the negative 1
-1(-4f^2-3f+6)=4f^2+3f-6
add
12f^2-9f+15+4f+3f-6
group like terms
12f^2+4f^2-9f+3f+15-6
add
16f^2-6f+9
aswer is 16f^2-6f+9
