All categories

3 years ago

How did scientists respond to Copernicus discovery

Chemistry

2 answers:

Maksim231197 [3]3 years ago

6 0

Answer:

Nicolaus Copernicus developed the Heliocentric model for the Solar System in the early 1500s. He was an astronomer, and he published a book in 1532 in which he proposed that the planets orbit the Sun rather than the Earth. The church reacted with outrage, and banned the book

Explanation:

Oksana_A [137]3 years ago

3 0

Answer:

You might be interested in

Match each scientist with thr contribution he made to the arrangement of the elements in the periodic table

Bas_tet [7]

Answer:

Dmitri Mendeleev

used patterns to predict undiscovered

elements

Johann Wolfgang Dobereiner

created groups of three elements,

each based on similar properties

John Newlands

arranged elements according to their

atomic mass

Antoine Lavoisier,

divided elements into four categories

✓

5 0

3 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,

Dafna1 [17]

Answer : The concentration of $A,B\text{ and }C$ at equilibrium are 0.132 M, 0.232 M and 0.168 M respectively.

Explanation :

The given chemical reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

$\Delta G^o=-RT \ln k$

where,

$\Delta G^o$ = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = $25^oC=273+25=298K$

Now put all the given values in the above relation, we get:

$-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k$

$k=5.45$

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

Initially 0.30 0.40 0

At equilibrium (0.30-x) (0.40-x) x

The expression of equilibrium constant will be,

$k=\frac{[C]}{[A][B]}$

$5.45=\frac{x}{(0.30-x)\times (0.40-x)}$

By solving the term x, we get

$x=0.168\text{ and }0.716$

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of $A$ at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of $B$ at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of $C$ at equilibrium = x = 0.168 M

3 0

4 years ago

Please help me, Thank you!

Phantasy [73]

Answer:

Explanation:

The atom shown in the image has 2 core electrons.

Electrons are the negatively charged particles within an atom. Therefore the total number of electrons surrounding the nucleus in the given specie is 7.

So;

We have 2 core electrons

And 5 valence electrons

The core electrons are the inner orbital electrons.

The valence electrons are the outermost electrons.

3 0

3 years ago

Could someone help me with this question? Thank you

KonstantinChe [14]

VALENCE ELECTRONS DETERMINE CHEMICAL PROPERTIES BECAUSE WHEN SAME ELEMENT REACT WITH DIFFERENT ELEMENTS THEN DIFFERENT COMPOUNDS ARE FORMING.FOR EXAMPLE HYDROGEN BOND WITH OXYGEN THEY FORM WATER AND WHEN HYDROGEN BOND WITH CHLORINE THEY FORM HCL WHICH SHOWS DIFFERENT PROPERTIES FROM WATER.

7 0

4 years ago

The combustion of propane may be described by the chemical equation,

olasank [31]

$\nu_{C_3H_8}=\frac{40.4}{\mu_{C_3H_8}}=$
$=\frac{40.4}{3A_C+8A_H}=\frac{40.4}{44}=$
$=\frac{9}{10}=0.9mol$
$1mol\ C_3H_8...5\ mol\ O_2 \\ 0.9mol\ C_3H_8...x\ mol\ O_2$
$x=\frac{0.9*5}{1}=4.5mol\ O_2$
$m=\mu_{O_2}*x=2*A_O*4.5=9*8=72g\ O_2$

6 0

4 years ago