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Nezavi [6.7K]
3 years ago
12

N2 + 3H2 = 2NH3

Chemistry
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

The answer to your question is:

a) Hydrogen

b) 850 g of NH3

c) 300 g of N2

Explanation:

                                       N2    +     3H2    ⇒    2NH3

N2 = 1000 g

H2 = 150 g

a. Identify the limiting reactant.

MW N2 = 28 g

MW H2 = 2 g        

MW NH3 = 17g                            

                                    N2    +     3H2    ⇒    2NH3

                                   28g ------  3(2)

                               1000 g ------   x

                              x = (1000 x 6)/ 28

                             x = 214.3 g of H2

Then, the limiting reactant is H2, because is necessary to have 214.3 g of H2 to react with 1000 g of N2, and there are only 150 g.

b. Calculate the theoretical yield in grams of NH3. __________

                                  N2    +     3H2    ⇒    2NH3                                

                                                    6g -----------2(17)g

                                               150g ---------   x

                                              x = (150 x 34) / 6

                                              x = 850 g of NH3

c. Calculate the grams of excess reactant. __________

                                  N2    +     3H2    ⇒    2NH3

                                 28g --------  6 g

                                  x ----------- 150 g

                                 x = (150 x 28)/ 6

                                 x = 700 g of N2

Excess reactant = 1000g  - 700g

                          = 300 g of N2

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= 148g/mol

no of moles = given mass / molar mass of the compound

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1.4×148=given mass

207.2 g

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Explanation:

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Answer:

The answer to your question is π = 12.47 atm

Explanation:

Data

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Process

1.- Calculate the moles of magnesium citrate

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2.- Calculate molarity

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3.- Calculate osmotic pressure

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