Flow-duration data are daily mean flow values measured over a specified time interval that have been exceeded various percentages of the specified time interval.

5 0

3 years ago

C(S)+O2(g)-->CO2(g)

soldi70 [24.7K]

Answer: The correct answer is 1.18 g.

Explanation:

We are given a chemical equation:

$C(S)+O2(g)\rightarrow CO_2(g)$

We know that at STP conditions:

22.4L of volume is occupied by 1 mole of a gas.

So, 2.21L of carbon dioxide is occupied by = $\frac{1}{22.4L}\times 2.21L=0.0986mol$ of carbon dioxide gas.

By Stoichiometry of the above reaction:

1 mole of carbon dioxide gas is produced by 1 mole of carbon

So, 0.0986 moles of carbon dioxide is produced by = $\frac{1}{1}\times 0.0986=0.0986mol$ of carbon.

Now, to calculate the mass of carbon, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of carbon = 0.0986 mol

Molar mass of carbon = 12 g/mol

Putting values in above equation, we get:

$0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g$

Hence, the correct answer is 1.18 g.

3 0

3 years ago

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