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4 years ago

8

The combustion of propane may be described by the chemical equation,

1 answer:

olasank [31]4 years ago

6 0

$\nu_{C_3H_8}=\frac{40.4}{\mu_{C_3H_8}}=$
$=\frac{40.4}{3A_C+8A_H}=\frac{40.4}{44}=$
$=\frac{9}{10}=0.9mol$
$1mol\ C_3H_8...5\ mol\ O_2 \\ 0.9mol\ C_3H_8...x\ mol\ O_2$
$x=\frac{0.9*5}{1}=4.5mol\ O_2$
$m=\mu_{O_2}*x=2*A_O*4.5=9*8=72g\ O_2$

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Answer:

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Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

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Part b

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The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

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Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

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$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

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Part d

Concentration after 4000 s is given as

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