Ideally, the van 't Hoff factor should be equal to the number of ions that make up a compound. In reality, van 't Hoff factors t
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The question is incomplete, here is the complete question:
An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?
<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
......(1)
Given mass of oxalic acid = 0.5842 g
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated oxalic acid solution
are the molarity and volume of diluted oxalic acid solution
We are given:
Putting values in above equation, we get:
Now, calculating the mass of glucose by using equation 1, we get:
Molarity of oxalic acid solution = 0.0026 M
Molar mass of oxalic acid = 90 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
Hence, the mass of oxalic acid in final solution is 0.0234 grams
Answer: A Bronsted-Lowry acid is defined as a substance that acts as a proton donor.
Explanation:
A substance that is able to donate a proton or hydrogen ion to another substance is a Bronsted-Lowry acid.
For example, HCl is a Bronsted-Lowry acid as it dissociates to give a hydrogen ion.
Thus, we can conclude that a Bronsted-Lowry acid is defined as a substance that acts as a proton donor.
<u>Answer:</u> The freezing point of solution is -5.11°C
<u>Explanation:</u>
Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:
The total number of ions present in the solution are 2.
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (NaCl) = 7.57 g
= Molar mass of solute (NaCl) = 58.44 g/mol
= Mass of solvent (liquid X) = 350.0 g
Putting values in above equation, we get:
To calculate the depression in freezing point, we use the equation:
where,
i = Vant hoff factor = 2
= molal freezing point depression constant = 6.90°C/m
m = molality of solution = 0.370 m
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
= 5.11 °C
Freezing point of water = 0°C
Freezing point of solution = ?
Putting values in above equation, we get:
Hence, the freezing point of solution is -5.11°C