Answer:
x = 3
Step-by-step explanation:
- Subtract 15 from each side, so it now looks like this: 21 = 7x
- Divide each side by 7 to cancel out the 7 next to x. It should now look like this: 3 = x
I hope this helps!
Answer: 
Step-by-step explanation:
Since, Here w represents the weight of the bottle.
And, According to the question, he acceptable weights, w, of a 20-ounce bottle of sports drink.
That is, weight of the bottle can not be higher than 20 or the it can be atleast 20.
Therefore, 
And, the weight can not be negative.
Therefore, 
Thus, the required inequality is,
Hello from MrBillDoesMath!
Answer:
Choice B ( (x+6)/5) )
Discussion:
y = f(x) = 5x - 6
To solve for the inverse of f, replace "y" by "x" and "x" by "y" in the original equation. That is, solve for "y" in
x = 5y -6 => add 6 to both sides
x + 6 = 5y => divide both sides by 5
y = (x+6)/5
"y" above is the inverse, which is Choice B
Thank you,
MrB
1)
The domain
is every value of x for which f(x) is a real number.
f(x) = 13 / (10-x)
The only x value that would not produce a real number for f(x) is 10, since you
cannot divide a number by zero. Answer is C
2)
F(x)
=(x-6)(x+6)/(x2 - 9)
The vertical asymptotes are x=3 and x=-3. Graph the function on a graphing
calculator to observe the behavior of the function at these points. There is
both a positive and negative vertical asymptote a both x=3 and x=-3. Keep in
mind that the denominator approaches zero at these points, and thus f(x) approaches
either positive or negative infinite, depending on whether the denominator, however small, is a positive or
negative number. Answer is B) 3, -3
3)
F(x) = (x2
+ 4x-7) / (x-7)
Although there is a vertical asymptote as x=7, there is no horizontal asymptote.
This makes sense. As X gets bigger, there is nothing to hold y back from
getting greater and greater. X2 is the dominant term, and it’s only
in the numerator. A) none
4)
(x2 +
8x -2) / (x-2)
This function is very similar in structure to the previous one. Same rules
apply. Dominant term only in the numerator means no horizontal asymptote.
A)None
5)
Our
function approaches 0 as x approaches infinite, and has a vertical asymptote at
x=2 and x=1.
Here’s an easy example: 10 / ((x-2)*(x-1)). At x=2 and x=1, there is both a
positive and negative vertical asymptote. As x approaches infinite, the
numerator is dominated by the denominator, which contains x (actually x2 ),
and thus y approaches zero.
X= 3.124 bc ur using Pythagoras Theorem so a squared + b squared = c squared :)
