Question

Genes a and b are 10 map units apart, b and c are 20 map units apart, and a and c are 30 map units apart. If a triple heterozygote is testcrossed, among 1,000 progeny, how many are expected to result from double crossovers if there is no interference?
а. 10;
b. 20;
c. can't be determined
d. 30;
e. 60;

Answer 1

Answer:

20 ( B )

Explanation:

Given data:

a and b are 10 map units apart

b and c are 20 map units apart

a and c = 30 map units apart

condition ; Triple heterozygote testcrossed

number of progeny = 1000

Determine the number of double crossover result

P( crossover between a and b ) = 10/100 = 0.1

P( crossover between b and c ) = 20/100 = 0.2

p( double crossover ) = 0.1 * 0.2 = 0.02

hence number of double crossovers = number of progeny * 0.02

                                                              = 1000 * 0.02 = 20