45.0 mL of a Naoh solution is titrated with 0.12 M HCl. If 29.6 mL is required for neutralization,
1 answer:
Answer:
M(NaOH) = 0.0789 M
Explanation:
NaOH + HCl ---> NaCl + H2O
M(NaOH)*V(NaOH) =M(HCl)*V(HCl)
M(NaOH) *45.0 mL (NaOH) = 0.12 M(HCl) * 29.6 mL(HCl)
M(NaOH) = 0.12*29.6/45.0 = 0.0789 M
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