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Alex17521 [72]
3 years ago
12

45.0 mL of a Naoh solution is titrated with 0.12 M HCl. If 29.6 mL is required for neutralization,

Chemistry
1 answer:
OLga [1]3 years ago
5 0

Answer:

M(NaOH) = 0.0789 M

Explanation:

NaOH + HCl ---> NaCl + H2O

M(NaOH)*V(NaOH) =M(HCl)*V(HCl)

M(NaOH) *45.0 mL (NaOH) = 0.12 M(HCl) * 29.6 mL(HCl)

M(NaOH) = 0.12*29.6/45.0  = 0.0789 M

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2 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
IgorC [24]

Answer:

669.48 kJ

Explanation:

According to the question, we are required to determine the heat change involved.

We know that, heat change is given by the formula;

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In this case;

Change in temperature = Final temp - initial temp

                                       = 99.7°C - 20°C

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Specific heat of water is 4.2 J/g°C

Therefore;

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But, 1 kJ = 1000 J

Therefore, heat change is 669.48 kJ

7 0
3 years ago
The density (mass/volume) of aluminum is 2.70 times. 103 kilograms per cubic meter (kg/m3). what is the mass of an aluminum cyli
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Mass of aluminum = (1.50 m^3)( 2.70 x 10^3 kg/m^3) = 4050 kg 

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<h3>What is Aluminum?</h3>
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7 0
2 years ago
Fe(NO3)2 not sure how to get the oxidation numbers of all elements
Shtirlitz [24]
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group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

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2 years ago
Can someone help please? :)
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1) This is a definition.

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9) The correct option is the explanation.

7 0
2 years ago
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