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3 years ago

45.0 mL of a Naoh solution is titrated with 0.12 M HCl. If 29.6 mL is required for neutralization,

Chemistry

1 answer:

OLga [1]3 years ago

5 0

Answer:

M(NaOH) = 0.0789 M

Explanation:

NaOH + HCl ---> NaCl + H2O

M(NaOH)*V(NaOH) =M(HCl)*V(HCl)

M(NaOH) *45.0 mL (NaOH) = 0.12 M(HCl) * 29.6 mL(HCl)

M(NaOH) = 0.12*29.6/45.0 = 0.0789 M

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Hello,

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Thus, any of the available expressions are suitable to quantify the rate of the reaction.

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