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Marina86 [1]
3 years ago
14

Calculate the mass of butane needed to produce 65.5 g of carbon dioxide

Chemistry
1 answer:
jeka943 years ago
6 0

You take the mass of carbon dioxide, 56.8g, divide by its molar mass, 44.01g/mol, to produce the moles of carbon dioxide. This is multiplied by the molar ratio of butane/CO2, (2/8) = 1/4, which gives the moles of butane required to produce the carbon dioxide.

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what is the reason for the difference between the values of the dry adiabatic lapse rate and the moist adiabatic lapse rate?
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Latent heat released during condensation offsets some of the cooling of a rising air parcel, causing the moist adiabatic lapse rate to have a smaller value.
6 0
3 years ago
What is the sum of the coefficients in the balanced chemical equation for the combustion of acetone, c3h6o(l), in air?
WITCHER [35]

The sum of the coefficients in the balanced chemical equation for combustion of acetone C3H6O in air  is 11

explanation

<h2>write a balanced chemical equation  for reaction</h2>

that is;  C3H6O + 4O2  → 3CO2 +3H2O

coefficient is the number in front of the chemical formula

the sum of coefficient is therefore= 1 ( in front of C3H6O) + 4 ( in front of O2) + 3 ( in front of CO2) + 3 ( in front of H2O) = 11

6 0
3 years ago
The maximum amount of product that can be produced from a given amount of reactant is known as ______________________.
vova2212 [387]

Answer:

The answer to your question is Theoretical yield

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3 0
3 years ago
Read 2 more answers
How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250
Grace [21]

<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of carbon dioxide = 8.5\times 10^{-5}M

Volume of solution = 0.550 L

Putting values in above equation, we get:

8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 4.675\times 10^{-3} moles of carbon dioxide will contain = (6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21} number of molecules

Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

3 0
3 years ago
Read 2 more answers
What are the coefficients that will balance the skeleton equation below?alcl3 + naoh → al(oh)3 + nacl?
Karo-lina-s [1.5K]
AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl

1 3 1 3
3 0
3 years ago
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